To solve this problem we will apply the Newtonian concept of gravitational acceleration produced by a planet. This relationship is given by:
![g = \frac{GM}{r^2}](https://tex.z-dn.net/?f=g%20%3D%20%5Cfrac%7BGM%7D%7Br%5E2%7D)
Where,
G = Gravitational Universal Constant
M = Mass of Earth
r = Radius
The values given are based on the constants of the earth, so they can be expressed as
![M_p = \frac{1}{100} M_e](https://tex.z-dn.net/?f=M_p%20%3D%20%5Cfrac%7B1%7D%7B100%7D%20M_e)
![r_p = \frac{1}{4} r_e](https://tex.z-dn.net/?f=r_p%20%3D%20%5Cfrac%7B1%7D%7B4%7D%20r_e)
The relationship of gravity would then be given:
![g_e = \frac{GM_e}{r_e^2}](https://tex.z-dn.net/?f=g_e%20%3D%20%5Cfrac%7BGM_e%7D%7Br_e%5E2%7D)
The relationship with the new planet, from the gravity of the earth would be given
![g_p = \frac{GM_p}{r_p^2}](https://tex.z-dn.net/?f=g_p%20%3D%20%5Cfrac%7BGM_p%7D%7Br_p%5E2%7D)
![g_p = \frac{G(1/100)M_e}{(1/4 r_e)^2}](https://tex.z-dn.net/?f=g_p%20%3D%20%5Cfrac%7BG%281%2F100%29M_e%7D%7B%281%2F4%20r_e%29%5E2%7D)
![g_p = \frac{GM_e 16}{100 r_e^2}](https://tex.z-dn.net/?f=g_p%20%3D%20%5Cfrac%7BGM_e%2016%7D%7B100%20r_e%5E2%7D)
![g_p = 0.16 \frac{GM_e}{r_e^2}](https://tex.z-dn.net/?f=g_p%20%3D%200.16%20%5Cfrac%7BGM_e%7D%7Br_e%5E2%7D)
![g_p = 0.16g_e](https://tex.z-dn.net/?f=g_p%20%3D%200.16g_e)
The relationship with the weight of the earth would be given as:
![W_e = m*g_e = 600N](https://tex.z-dn.net/?f=W_e%20%3D%20m%2Ag_e%20%3D%20600N)
![W_p = m*g_p = m(0.16g_p)](https://tex.z-dn.net/?f=W_p%20%3D%20m%2Ag_p%20%3D%20m%280.16g_p%29)
![W_p = (m*g_p)(0.16)](https://tex.z-dn.net/?f=W_p%20%3D%20%28m%2Ag_p%29%280.16%29)
![W_p = 600*0.16](https://tex.z-dn.net/?f=W_p%20%3D%20600%2A0.16)
![W_p = 96N](https://tex.z-dn.net/?f=W_p%20%3D%2096N)
Therefore the weigh on this planet would be 96N
Forgot to measure the volume in the beginning so the student could tell the difference
Answer:
v = 6.89 [m/s]
velocity = 0
Explanation:
To solve this problem we must use the definition of speed which is defined by the following expression of physics, such as the relationship between distance and time.
v = x/t
where:
v = speed [m/s]
x = distance = 400 [m]
t = time = 58 [s]
v = 400/58
v = 6.89 [m/s]
The velocity is a vector, since the racing car moves in circles IE its movement started where it ended, its velocity is zero.