A TLC plate showed 2 spots with Rf values of 0.25 and 0.26. The plate was removed from the developing chamber, the residual solv
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Answer: The volume of hydrogen gas produced will be, 12.4 L
Explanation : Given,
Mass of = 54.219 g
Number of atoms of =
Molar mass of = 98 g/mol
First we have to calculate the moles of and
.
and,
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 3 mole of react with 2 mole of
So, 0.553 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 3 mole of react to give 3 mole of
So, 0.553 mole of react to give 0.553 mole of
Now we have to calculate the volume of gas at STP.
As we know that, 1 mole of substance occupies 22.4 L volume of gas.
As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas
So, 0.553 mole of hydrogen gas occupies volume of hydrogen gas
Therefore, the volume of hydrogen gas produced will be, 12.4 L
Answer:
The average velocity of the airplane for this trip is 1684.21 km/h
Explanation:
Average velocity is the rate of change of displacement with time. That is,
Average velocity = = Δx / Δt =
Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.
From,
Velocity =
Time =
Therefore, Time =
Time = 2.1h
This is the time taken before the airplane encounters a wind.
Hence, t1 = 2.1h
Now, For the time taken by the airplane when it encounters a wind
Also from,
Velocity =
Time =
Therefore, Time =
Time = 1.625h
Hence, t2 = 1.625h
Now, to calculate the average velocity
Average velocity =
x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h
Hence, Average velocity =
Average velocity = 1684.21 km/h