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AleksAgata [21]

3 years ago

9

What is the difference of a mineral and a gem?

1 answer:

Citrus2011 [14]3 years ago

4 0

A gem is a crystalized mineral.

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The law of reflection states that the angle of incidence is equal to the angle of reflection.

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Hello,

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Explain the role of each factor in chemical weathering (water, acid, and air).

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How many elements are identified in tearms of their atoms

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What is one takeaway you have about future sea levels rising ?

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The equilibrium constant, K., for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC13(E) Calculate the equilibrium

lord [1]

Answer:

The equilibrium concentration of $PCl_5=0.228 M$ .

The equilibrium concentration of $PCl_3=0.280 M -0.228 M=0.052M$ .

The equilibrium concentration of $Cl_2=0.280 M -0.228 M=0.052M$ .

Explanation:

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = $K_c=83.3$

Moles of $PCl_3 = 0.280 mol$

Concentration of $[PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M$

Moles of $Cl_ = 0.280 mol$

Concentration of $[Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M$

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

Initial: 0.280 0.280 0

At eq'm: (0.280-x) (0.280-x) x

We are given:

$[PCl_3]_{eq}=(0.280-x)$

$[Cl_2]_{eq}=(0.280-x)$

$[PCl_5]_{eq}=x$

Calculating for 'x'. we get:

The expression of $K_{c}$ for above reaction follows:

$K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}$

Putting values in above equation, we get:

$83.3=\frac{x}{(0.280-x)\times (0.280-x)}$

On solving this quadratic equation we get:

x = 0.228, 0.344

0.228 M < 0.280 M< 0.344 M

x = 0.228 M

The equilibrium concentration of $PCl_5=0.228 M$ .

The equilibrium concentration of $PCl_3=0.280 M -0.228 M=0.052M$ .

The equilibrium concentration of $Cl_2=0.280 M -0.228 M=0.052M$ .

4 0

3 years ago