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Sergio [31]
3 years ago
6

A scientist did an investigation on the growth of koi fish. He selected forty newly hatched koi from the same clutch of eggs. He

separated the koi into four groups and placed each group in a different sized pond. None of the ponds had any predators that would eat the koi fish. The amount of food available to the koi and the water quality of each pond differed based on the size of the pond. Larger ponds had more food available and better water quality as the fish grew.
After 15 months, the scientist measured the length of each koi fish. Using these measurements, he came up with an average koi size for each pond.

Effect of Pond Size on Koi Fish Growth

Size of Pond Average Length of Koi
500 gallons 18.2 centimeters
1000 gallons 25.6 centimeters
2500 gallons 30.8 centimeters
5000 gallons 35.3 centimeters

Based on the scientist's results, which of the following is true?
A.
Koi fish grow fastest in ponds with poor water quality.
B.
Koi fish grow fastest in ponds with a high population density.
C.
The growth of koi fish is determined entirely by genetics.
D.
The growth of koi fish is affected by the environment of the fish.
Chemistry
1 answer:
Luda [366]3 years ago
8 0
D have a good day my dude
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A piston confines 0.200 mol Ne(g) in 1.20 at 25 degree C. Two experiments are performed. (a) The gas is allowed to expand throug
djyliett [7]

Answer:

The second experiment (reversible path) does more work

Explanation:

Step 1:

A piston confines 0.200 mol Ne(g) in 1.20L at 25 degree °C

<em>(a) The gas is allowed to expand through an additional 1.20 L against a constant of 1.00atm</em>

<em></em>

Irreversible path: w =-Pex*ΔV

⇒ with Pex = 1.00 atm

⇒ with ΔV = 1.20 L

W = -(1.00 atm) * 1.20 L

W = -1.20L*atm *101.325 J /1 L*atm = -121.59 J

<em>(b) The gas is allowed to expand reversibly and isothermally to the same final volume.</em>

<em></em>

W = -nRTln(Vfinal/Vinitial)

⇒ with n = the number of moles = 0.200

⇒ with R = gas constant = 8.3145 J/K*mol

⇒ with T = 298 Kelvin

⇒ with Vfinal/Vinitial  = 2.40/1.20 = 2

W = -(0.200mol) * 8.3145 J/K*mol *298K *ln(2.4/1.2)

W = -343.5 J

The second experiment (reversible path) does more work

7 0
3 years ago
How many grams of KCl are needed to prepare 0.750 L of a 1.50 M solution in water?
dlinn [17]

Answer: Option A) 83.9g

Explanation:

KCl is the chemical formula of potassium chloride.

Given that,

Amount of moles of KCl (n) = ?

Volume of KCl solution (v) = 0.75L

Concentration of KCl solution (c) = 1.5M

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 1.5M x 0.75L

n = 1.125 mole

Now given that,

Amount of moles of KCl (n) = 1.125

Mass of KCl in grams = ?

For molar mass of KCl, use the molar masses of:

Potassium, K = 39g;

Chlorine,Cl = 35.5g

KCl = (39g + 35.5g)

= 74.5g/mol

Since, amount of moles = mass in grams / molar mass

1.125 mole = m / 74.5g/mol

m = 1.125 mole x 74.5g/mol

m = 83.81g

Thus, 83.9 grams of KCl are needed to prepare 0.750 L of a 1.50 M solution in water

3 0
2 years ago
When solid ammonium chloride dissociates at a certain temperature in a 0.500 dm3 container, ammonia and hydrogen chloride are fo
SIZIF [17.4K]
1) Reaction

<span>NH4Cl(s) ---> NH3(g) + HCl(g)


2) equilibrium equation, Kc


Kc = [NH3] * [HCl]


3) Table of equilibrium formation



step               concentrations
                       </span>
<span>                            NH4Cl(s)                     NH3(g)             HCl(g)


start                      1.000 mole                     0                    0


react                        - x


produce                                                       +x                  + x
                         ------------------                ----------              -----------

end                         1 - x                             +x                    +x
            

1 - x = 0.3 => x = 1 - 0.3 = 0.7


[NH3] = [HCl] = 0.7/0.5 liter = 1.4                (I used 0.500 dm^3 = 0.5 liter)


4) Equilibrium equation:


Kc = [NH3] [HCl] = (1.4)^2  = 1.96


Which is the number that you were looking for.


Answer: Kc = 1.96
</span>
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3 years ago
The reaction of hydrogen gas with oxygen gas is what type of reaction precipitation single replacement
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To evaluate the accuracy of a measurement, the measured value must be compared to the correct value. To evaluate the precision of a measurement, you must compare the values of two or more repeated measurements.
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