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3 years ago

Solve the system of equations. -5x+2y=9 y=7x Help!

Mathematics

2 answers:

fiasKO [112]3 years ago

3 0

Answer:

It doesn't make sense, i can solve this problem

stiks02 [169]3 years ago

3 0

Answer:

x = 1

y = 7

Step-by-step explanation:

Given

-5x + 2y = 9

y = 7x

Substitute 7x for y in the first equation.

We have,

-5x + 2(7x) = 9

-5x + 14x = 9

9x = 9

Divide both sides by 9

9x/9 = 9/9

x = 1

Substitute 1 for x In either of the above equations to get y.

Using the second equation,

We have

y = 7x

Therefore

y = 7 x 1

y = 7

x = 1 and

y = 7

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Read 2 more answers

Suppose that the functions s and t are defined for all real numbers x as follows.

jeka94

Answer:

$(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39$

Step-by-step explanation:

Given functions are:

$s(x)= x+6\\t(x)= 4x^2$

We have to find:

(s.t)(x) => this means we have to multiply the two functions to get the result.

So,

$(s.t)(x) = s(x)*t(x)\\= (x+6)(4x^2)\\=4x^2.x+4x^2.6\\=4x^3+24x^2$

Also we have to find

(s-t)(x) => we have to subtract function t from function s

$(s-t)(x) = s(x) - t(x)\\= (x+6) - (4x^2)\\=x+6-4x^2$

Also we have to find,

(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

$(s+t)(x) = s(x)+t(x)\\= x+6+4x^2$

Putting x = -3

$= -3+6+4(-3)^2\\=-3+6+4(9)\\=3+36\\=39$

Hence,

$(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39$

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3 years ago