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astraxan [27]
3 years ago
12

A student squeezes several oranges to make a glass of orange juice. The juice contains pieces of orange pulp mixed with the juic

e. Explain why this drink can be considered a combination of a suspension and a solution.
Physics
2 answers:
Mars2501 [29]3 years ago
7 0

<span>In </span>chemistry<span>, a suspension<span> is a heterogeneous mixture containing solid particles that are sufficiently large for </span></span>sedimentation<span>. Usually they must be larger than one </span>micrometer<span>. A Suspension is a heterogeneous mixture in which the solute particles do not dissolve but get suspended throughout the bulk of the medium. a </span>solution<span> is a </span>homogeneous mixture<span> <span>composed of two or more substances. In such a mixture, a </span>solute<span> is a substance </span></span>dissolved<span> <span>in another substance, known as a </span>solvent.. it is considered a solution and suspension because the orange juice mix with water while the pulp did not and retained as solid</span>

nasty-shy [4]3 years ago
7 0

Answer:

The juice contains sugars, plant pigments, and other chemicals dissolved in water. This is a solution.  The pieces of orange pulp will rise to the top or settle to the bottom of the juice if it is allowed to sit.  The pieces of pulp mixed with the juice form a suspension.

Explanation:

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The water required to pump all the water to a platform 2 feet above the top of the pool is  is 6061310.32 foot-pound.

Explanation:

Given that,

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Work = 4329507.37572

Height = 2 feet

Let's look at a horizontal slice of water at a height of h from bottom of pool

We need to calculate the area of slice

Using formula of area

A=\pi r^2

Put the value into the formula

A=\pi\times21^2

A=441\pi\ feet^2

Thickness of slice t=\Delta h\ ft

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V=(441\pi\times\Delta h)\ ft^3

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Using formula of force

F=W\times V

Where, W = water weight

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Put the value into the formula

F=62.5\times(441\pi\times\Delta h)

F=27562.5\pi\times\Delta h\ lbs

We need to calculate the work done

Using formula of work done

W=F\times d

Put the value into the formula

W=27562.5\pi\times\Delta h\times(10-h)\ ft\ lbs

We do this by integrating from h = 0 to h = 10

We need to find the total work,

Using formula of work done

W=\int_{0}^{h}{W}

Put the value into the formula

W=\int_{0}^{10}{27562.5\pi\\times(10-h)}dh

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W=27562.5\pi(10\times10-\dfrac{100}{2}-0)

W=4329507.37572

To pump 2 feet above platform, then each slice has to be lifted an extra 2 feet,

So, the total distance to lift slice is (12-h) instead of of 10-h

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Using formula of work done

W=\int_{0}^{h}{W}

Put the value into the formula

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W=1929375\pi

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Hence, The water required to pump all the water to a platform 2 feet above the top of the pool is  is 6061310.32 foot-pound.

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