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Answer:
The atomic mass of the other isotope = 106.905 amu
Explanation:
Step 1: Data given
Atomic mass of silver = 107.868 amu
Ag109 isotope has an atomic mass of 108.905 amu = 48.16 %
Step 2: Calculate the abundance of the other isotope
100.0 % - 48.6 % = 51.84 %
107.868 = 0.4816*108.905 + 0.5184*X
55.419352 = 0.5184X
X = 106.905
The atomic mass of the other isotope = 106.905 amu
E°cell =+1.34V
F= 96485C mol-1
3Cu(s) →3CU2+(aq) +6e-E°ck= -0.34V
2MnO4-(aq) +8H+(aq)+6e→2MnO2(s)+4H2O(l)/3CU(s) + 2MnO4-(aq)+8H+(aq)→3CU 2+((aq)+ 2MnO2(s)+4H2O (l)
E°red= +1.68V/E°cell=+1.34V
ΔG° = -nFE°cell = -6×96485×1.34 = -775.7kJ/mol
Answer:
Acceleration is the rate of change in velocity
Carbon is found in all four.