Using newton's law of gravity on a 1kg mass near the star. G is newton's grav constant. g is acceleration of grav at starGMstar/r^2 = gstar
For transverse waves<span> the displacement of the medium is perpendicular to the direction of propagation of the </span>wave<span>. A ripple on a pond and a </span>wave<span> on a string are easily visualized </span>transverse waves<span>. Hope this helps. Have a nice day. Feel free to ask more questions.</span>
Explanation:
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Answer:
The boat's acceleration is 4 m/s²
Explanation:
This question seeks to test the knowledge of acceleration and how to calculate acceleration when the speed is provided. Hence, the formula for acceleration would be used here.
Acceleration (m/s²) = speed (in m/s) ÷ time (in seconds)
Acceleration = 80 m/s ÷ 20 secs
Acceleration = 4 m/s² or 4 ms⁻²
The boat's acceleration is 4 m/s²
Answer:
5. -24 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s².
mathematically,
a = dv/dt ............................ Equation 1
Where a = acceleration, dv/dt = is the differentiation of velocity with respect to time.
But
v = dx(t)/dt
Where,
x(t) = 27t-4.0t³...................... Equation 2
Therefore, differentiating equation 2 with respect to time.
v = dx(t)/dt = 27-12t²............. Equation 3.
Also differentiating equation 3 with respect to time,
a = dv/dt = -24t
a = -24t .................... Equation 4
from the question,
At the end of 1.0 s,
a = -24(1)
a = -24 m/s².
Thus the acceleration = -24 m/s²
The right option is 5. -24 m/s²