Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :

B is magnetic field

So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.
Explanation:
Amperage is the unit of electric current. It describes the strength of the electric current in a circuit.
The voltage is the driving force of the current in a circuit
Power is a function of voltage and current in the circuit.
Current is designate as I
Voltage as V
Power as P
I = 
Where R is the resistance to flow of electricity
P = I x V = 
The unit of power is watts and voltage is volts
learn more:
Voltage brainly.com/question/6949231
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