Question: The force between a pair of 0.005 C is 750 N. What is the distance between them?
Answer:
17.32 m
Explanation:
From coulomb's Law,
F = kqq'/r²........................... Equation 1
Where F = Force between the force, q' and q = both charges respectively, k = coulomb's constant, r = distance between both charges.
make r the subject of the equation above
r = √(kqq'/F)..................... Equation 2
From the question,
Given: q = q' = 0.005 C, F = 750 N
Constant: k = 9.0×10⁹ Nm²/C².
Substitute these values into equation 2
r = √(9.0×10⁹×0.005×0.005/750)
r = √(300)
r = 17.32 m.
Hence the distance between the pair of charges = 17.32 m
D.) Rubbing your hands together
Hope this helps! ( brainleist??)
Answer:
A,B,C,D, and F are correct
Explanation:
I think WA in friction means Water Absorption.
Answer:
Final speed of the rocket, 
Explanation:
It is given that,
Impulse delivered by an engine, J = 3.5 kg-m/s
Mass of the rocket, m = 120 g = 0.12 kg
To find,
The final speed of the rocket
Solution,
We know that the impulse is equal to the product of mass and velocity o it is equivalent to the change in momentum of an object.
So, the final speed of the rocket once the engine has fired is 29.16 m/s.
