What is the concentration of a phosphoric acid solution of a 25.00 mL sample if the acid requires 42.24 mL of 0.135 M NaOH for n
2 answers:
Answer: The volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.
Explanation:
According to the neutralization law,
where,
= molarity of NaOH solution = 0.135 M
= volume of NaOH solution = 42.24 ml
= molarity of
solution = ?M
= volume of
solution = 25 ml
= valency of
= 1
= valency of
= 3
Therefore, the concentration of 0.076 M of phosphoric acid of a 25 ml is required to neutralize 42.24 ml of 0.135 M NaOH.
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Answer : The resulting solution will have a pH of 7.
Explanation:
Whenever acid and base reacts with each other to form water molecule is called Neutralization reaction. This water molecules is formed from the hydronium ion () from acid and hydroxide ion(
) from base.
When the equal volumes of acid and base of equal strength are combined, the resulting pH of the solution becomes 7.
The pH 7 value means that the solution is neutral.