What is the concentration of a phosphoric acid solution of a 25.00 mL sample if the acid requires 42.24 mL of 0.135 M NaOH for n
2 answers:
Answer: The volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.
Explanation:
According to the neutralization law,
where,
= molarity of NaOH solution = 0.135 M
= volume of NaOH solution = 42.24 ml
= molarity of
solution = ?M
= volume of
solution = 25 ml
= valency of
= 1
= valency of
= 3
Therefore, the concentration of 0.076 M of phosphoric acid of a 25 ml is required to neutralize 42.24 ml of 0.135 M NaOH.
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<u>Answer:</u> To calculate the pH of the buffer composed of , we use the
<u>Explanation:</u>
Phosphoric acid is a triprotic acid and it will undergo three dissociation reaction each having their respective dissociation constants.
The chemical equation for the first dissociation reaction follows:
The chemical equation for the second dissociation reaction follows:
The chemical equation for the third dissociation reaction follows:
To form a buffer composed of , we use the
of second dissociation process
To calculate the , we use the equation:
To calculate the pH of buffer, we use the equation given by Henderson Hasselbalch:
We are given:
= negative logarithm of second acid dissociation constant of phosphoric acid = 7.21
= concentration of conjugate base
= concentration of weak acid
Hence, to calculate the pH of the buffer composed of , we use the