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3 years ago

PLEASE HELP.

Physics

2 answers:

Lelu [443]3 years ago

5 0

The frequency of the wave will not change

zalisa [80]3 years ago

4 0

Answer:

the frequency of the wave wont change because it just wont and i got it right

Explanation:

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A record of travel along a straight path is as follows:

nignag [31]

Answer:

a) Total displacement = 3986.54 m

b) Average speeds

Leg 1 -> 11.22 m/s

Leg 2 -> 22.44 m/s

Leg 3 -> 11.20 m/s

Complete trip -> 21.63 m/s

Explanation:

a) Leg 1:

Initial velocity, u = 0 m/s

Acceleration , a = 2.04 m/s²

Time, t = 11 s

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

s = 0 x 11 + 0.5 x 2.04 x 11²

s = 123.42 m

Leg 2:

We have equation of motion v = u + at

Initial velocity, u = 0 m/s

Acceleration , a = 2.04 m/s²

Time, t = 11 s

Substituting

v = 0 + 2.04 x 11 = 22.44 m/s

We have equation of motion s= ut + 0.5 at²

Initial velocity, u = 22.44 m/s

Acceleration , a = 0 m/s²

Time, t = 2.85 min = 171 s

Substituting

s= ut + 0.5 at²

s = 22.44 x 171 + 0.5 x 0 x 171²

s = 3837.24 m

a) Leg 3:

Initial velocity, u = 22.44 m/s

Acceleration , a = -9.73 m/s²

Time, t = 2.31 s

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

s = 22.44 x 2.31 + 0.5 x -9.73 x 2.31²

s = 25.88 m

Total displacement = 123.42 + 3837.24 + 25.88 = 3986.54 m

Average speed is the ratio of distance to time.

b) Leg 1:

$v_{avg}=\frac{123.42}{11}=11.22m/s$

Leg 2:

$v_{avg}=\frac{3837.24}{171}=22.44m/s$

Leg 3:

$v_{avg}=\frac{25.88}{2.31}=11.20m/s$

Complete trip:

$v_{avg}=\frac{3986.54}{11+171+2.31}=21.63m/s$

5 0

3 years ago

____________ are used to calculate the distance a continent has moved in a year. a. Space satellites c. Laser beams b. Mirrors d

Law Incorporation [45]

Space satellites, laser beams, mirrors are used to calculate the distance a continent has moved in a year.

Therefore, your correct answer would be "all of the above".

4 0

3 years ago

Select the type of volcanoes that frequently erupt violently?

xxTIMURxx [149]

the correct answer would be

6 0

3 years ago

A projectile is launched at ground level with an initial speed of 50.0 m/s at an angle of 30.0Â° above the horizontal. it strike

Anni [7]

x = 129.9 m y = 30.9 m First, let's calculate the horizontal and vertical velocities involved h = 50.0cos(30) = 43.30127 m/s v = 50.0sin(30) = 25 m/s The horizontal distance is simply the horizontal velocity multiplied by the time, so 43.30127 m/s * 3 s = 129.9 m So the horizontal distance traveled is 129.9 m, so x = 129.9 m The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2 d = 75 m - 4.9 m/s^2 * 9 s^2 d = 75 m - 44.1 m d = 30.9 m So the vertical distance traveled is 30.9 m, so y = 30.9 m

8 0

4 years ago

How many photons are absorbed during the dental x-ray?

MariettaO [177]

E=hc/wav. len
E = (6.62 x 10^-34 x 3 x 10^8)/0.0275 x 10^-9
E = 7.22182 x 10^-15 J
To convert to eV divide by 1.6 x 10^-19
E = 7.22182 x 10^-15/1.6 x 10^-19 eV
E =45.36 x 10^3 eV
Th energy, E, of a single x-ray photon in eV is = 45.36keV.

Number of photons, n = total energy/ energy of photon
n = 3.85 x 10^-6/7.22182 x 10^-15
n = 5.33 x 10^8 photons

8 0

3 years ago