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Verdich [7]
4 years ago
8

If a 240 N force F1 is applied to the piston with the 4 cm diameter, what is the magnitude of the force F2 that can be resisted

by the piston with the 10 cm diameter
Physics
1 answer:
egoroff_w [7]4 years ago
5 0

Answer:

38.4 N.

Explanation:

From pascal's principle,

Pressure applied to the first piston = pressure applied to the second piston

F1/A1 = F2/A2 ....................... Equation 1

Where F1 = Force applied to the first piston, A1 = Area of the first piston, F2 = force applied to the second piston, A2 = Area of the second piston.

But,

A1 = πd₁²/4................... Equation 2

A2 = πd₂²/4............... Equation 3

Where d₁ and d₂ are the diameter of the first and second piston respectively.

Substitute equation 2 and equation 3 into equation 1

F1/πd₁²/4 = F2/πd₂²/4

F1/d₁² = F2/d₂² ................. Equation 4

make F2 the subject of the equation,

F2 = (F1×d₂)/d₁²................ Equation 5

Given: F1 = 240 N, d₁ = 4 cm, d₂ = 10 cm.

Substitute into equation 5

F2 = (240×4²)/10²

F2 = 38.4 N.

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Buckets and a Pulley Two buckets of sand hang from opposite ends of a rope that passes over an ideal pulley. One bucket is full
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Answer:

A: T = 120 N

B: T = 88.42 N

C: T = 70 N

Explanation:

Part A:

Since, the lighter bucket is supported by my had. So, the only unbalanced force in the system is the weight of heavier bucket. Hence, the tension in rope will be equal to the weight of heavier bucket.

<u>T = 120 N</u>

<u></u>

Part B:

This is the case where, two masses hang vertically on both sides of the pulley. To find the tension in such case we have the formula:

T = (2 m₁m₂g)/(m₁+m₂)

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m₁ = mass of lighter object = W₂/g = (70 N)/(9.8 m/s²) = 7.14 kg

g = 9.8 m/s²

Therefore,

T = [(2)(12.24 kg)(7.14 kg)(9.8 m/s²)]/(12.24kg + 7.14 kg)

T = 1713.6 N.kg/19.38 kg

<u>T = 88.42 N</u>

<u></u>

Part C:

Since, the heavier bucket is on ground. So, its weight is balanced by the normal reaction of the ground. The only unbalanced force in the system is the weight of lighter bucket. Hence, the tension in rope will be equal to the weight of lighter bucket.

<u>T = 70 N</u>

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