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Slav-nsk [51]
3 years ago
6

Both renewable and nonrenewable resources are used within our society. How do the uses of nonrenewable resources compare to the

uses of renewable resources?
a.
Nonrenewable resources have more applications than renewable resources.
b.
Certain types of renewable energy can be used for as many applications as certain types of nonrenewable resources.
c.
There are more sources of nonrenewable energy than renewable energy.
d.
Nonrenewable resources have fewer applications than renewable resources.
Chemistry
2 answers:
madreJ [45]3 years ago
7 0

Renewable sources are which can be gained again and again from nature

for example : sun energy or wind energy

non renewable: these once consumed cannot be regained

example : fossil fuels

Now both can be used for many kinds of applications however the resources so we can say that Certain types of renewable energy can be used for as many applications as certain types of nonrenewable resources

Mila [183]3 years ago
4 0

Renewable energy has the potential to have all the same applications as non-renewable. But we currently don't have the resources and potential.

So I would say the answer would be B, but this question is somewhat confusing.

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Which statement defines reduction potential when considering a pair of half-cell reactions?
Ivahew [28]
The  half reaction  with  the   the  greater SRP has  a  greater  tendency  to  gain  electrons  is  the   definition of  reduction  potential when  considering  a pair of  half  cell  reactions.This  reduction potential  is  measured  against  hydrogen   electrode  which  is  standard  electrode. 
6 0
3 years ago
A system fitted with a piston expands when it absorbs 53.1 ) of heat from the surroundings. The piston is working against a pres
Hoochie [10]

Answer:

d. 60.8 L

Explanation:

Step 1: Given data

  • Heat absorbed (Q): 53.1 J
  • External pressure (P): 0.677 atm
  • Final volume (V2): 63.2 L
  • Change in the internal energy (ΔU): -108.3 J

Step 2: Calculate the work (W) done by the system

We will use the following expression.

ΔU = Q + W

W = ΔU - Q

W = -108.3 J - 53.1 J = -161.4 J

Step 3: Convert W to atm.L

We will use the conversion factor 1 atm.L = 101.325 J.

-161.4 J ×  1 atm.L/101.325 J = -1.593 atm.L

Step 4: Calculate the initial volume

First, we will use the following expression.

W = - P × ΔV

ΔV = - W / P

ΔV = - 1.593 atm.L / 0.677 atm = 2.35 L

The initial volume is:

V2 = V1 + ΔV

V1 = V2 - ΔV

V1 = 63.2 L - 2.35 L = 60.8 L

7 0
2 years ago
A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant?
KengaRu [80]

Answer:

d. Copper (II) sulfate

Explanation:

Given data:

Mass of Al = 1.25 g

Mass of CuSO₄ = 3.28 g

What is limiting reactant = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂ (SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 1.25 g/ 27 g/mol

Number of moles = 0.05 mol

Number of moles of CuSO₄:

Number of moles = mass/molar mass

Number of moles = 3.28 g/ 159.6 g/mol

Number of moles = 0.02 mol

now we will compare the moles of reactant with product.

               Al           :           Al₂ (SO₄)₃

                 2          :             1

               0.05       :          1/2×0.05=0.025 mol

                Al           :            Cu

                 2            :              3

               0.05         :            3/2×0.05 = 0.075 mol

         CuSO₄           :           Al₂ (SO₄)₃

                3             :             1

               0.02         :          1/3×0.02=0.007 mol

         CuSO₄           :            Cu

               3               :              3

               0.02         :              0.02

Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.

4 0
3 years ago
KHP is a monoprotic acid which provides one H+ ion. How would your results be affected if a diprotic acid (such as sulfuric acid
kari74 [83]

Explanation:

A.

In a diprotic acid, 2 moles of H+ ions is released. Therefore, number of moles of H+ in a diprotic acid = 2 × number of moles of H+ of monoprotic acid.

B.

Equation of the reaction

2NaOH + H2SO4 --> Na2SO4 + 2H2O

Number of moles of H2SO4 = molar concentration × volume

= 0.75 × 0.0105

= 0.007875 moles.

By stoichiometry, since 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, number of moles of NaOH = 2 × 0.007875

= 0.01575 moles.

Molar concentration of NaOH = number of moles ÷ volume

= 0.01575 ÷ 0.0175

= 0.9 M of NaOH.

7 0
3 years ago
Which of the following units is used to measure force ?
Sati [7]
C.) Newton. & it's S.I. Unit of Force.

Hope this helps!
3 0
3 years ago
Read 2 more answers
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