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Viktor [21]
4 years ago
12

Which statement defines reduction potential when considering a pair of half-cell reactions?

Chemistry
1 answer:
Ivahew [28]4 years ago
6 0
The  half reaction  with  the   the  greater SRP has  a  greater  tendency  to  gain  electrons  is  the   definition of  reduction  potential when  considering  a pair of  half  cell  reactions.This  reduction potential  is  measured  against  hydrogen   electrode  which  is  standard  electrode. 
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M= 2 kg, a = 2 m/s^2. <br><br> Find F
saul85 [17]

Answer:

<h3>F=4k.gm/s^2</h3>

Explanation:

<h3>F=m×a</h3><h3>f=2k.g×2m/s^2</h3><h3>f=4k.gm/s^2</h3>
8 0
3 years ago
Sort these elements into pairs that would most likely exhibit similar chemical properties Br ,Mg ,F ,Sr ,S ,O
Lapatulllka [165]
The elements in the periodic table are arranged in columns - elements in the same column exhibit similar properties.
Mg and Sr are in the same column (period I)
Br and F  (period XVII - 17)
S and O (period XVI - 16)
8 0
4 years ago
A 10.00 g sample of a compound containing only carbon, hydrogen, and oxygen forms 23.98 g CO2 and 4.91 g H2O upon complete combu
yanalaym [24]
We can determine the empirical formula by first converting each of the grams to moles. remember to do this, first, we need the molar mass of the molecules which can be calculated by adding the mass of the atoms from the periodic table. 

molar mass of CO2= 44.0 g/mol
molar mass of H2O= 18.02 g/mol

now, lets determine the grams of each atom

Carbon: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C

Hydrogen: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H

Oxygen: 10.0 - (6.54 + 0.55) = 2.91 g O

Now let's convert each mass to moles.

C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol

now that we have the moles of each atom, we need to divide them by the smallest value to find the ration. If you do not get the whole number, you need to multiply until to get a whole number.

C:  0.54 mol / 0.18 mol = 3
H:  0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1

empirical formula--> C₃H₃O



4 0
4 years ago
How many moles are in 7.46 x 1025 particles of iron
sladkih [1.3K]

Answer:

1 mole of iron =6.023×10^23 particles

1 particles of iron=1/6.023×10^23 mole

7.46×10^25 particles =1/6.023×10^23×7.46×10^25

=1.238×10^48 mole is a required answer.

4 0
3 years ago
Is trimming a bush because it grows too tall a chemical or physical change
professor190 [17]

Answer:

Physical Change

Explanation:

The bush is changing shapes, not changing what it is.

8 0
4 years ago
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