Answer : The original concentration of copper (II) sulfate in the sample is, 
Explanation :
Molar mass of Cu = 63.5 g/mol
First we have to calculate the number of moles of Cu.
Number of moles of Cu = 
Now we have to calculate the number of moles of 
Number of moles of Cu = Number of moles of 
Number of moles of
= 
Now we have to calculate the molarity of 

Now put all the given values in this formula, we get:

To change mol/L into g/L, we need to multiply it with molar mass of 
Molar mass of
= 159.609 g/mL
Concentration in g/L = 
Thus, the original concentration of copper (II) sulfate in the sample is, 
Answer: a)
: anode
b.
: cathode
c.
: anode
Explanation:
Electrochemical cell is a device which converts chemical energy into electrical energy. It consist of two electrodes, anode and cathode.
Oxidation i.e. loss of electrons , which results in an increase in oxidation number occurs over anode.
Reduction i.e. gain of electrons, which results in decrease in oxidation number occurs over cathode.
a.
: oxidation : anode
b.
: reduction : cathode
c.
: oxidation : anode
Answer:
Ocean Currents
Explanation:
The correct answer is Ocean currents.
When the earth receives solar radiation, a large fraction of this incident radiation is usually absorbed by the oceans and the seas, which become warm. Usually, equitorial regions are the ones that have this phenomenon. Now, when ocean currents are flowing from the equator, they usually carry this warm water with them thereby moving the greatest amount of heat from the equator on its way out.
For example, In the Pacific Ocean, there is a current known as Alaska Current that carries warm water in the northward direction thereby making Anchorage which is Alaska's largest city to have a much mild weather than the inland areas with the same latitude.
2BF₃ + 3Li₂SO₃ ----> B₂(SO₃)₃ + <u>6LiF
</u>:)<u>
</u>
Mass C₆H₈O₇ : 0.531484 g
<h3>Further explanation</h3>
Reaction
3NaHCO₃ (aq) + C₆H₈O₇ (aq) → 3 CO₂ (g) + 3 H₂O (l) + Na₃C₆H₅O₇ (aq)
MW NaHCO₃ : 84 g/mol
mass NaHCO₃ : 7.10² mg=0.7 g
mol NaHCO₃ :

mol C₆H₈O₇ :

MW C₆H₈O₇ : 192 g/mol
mass C₆H₈O₇ :
