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kakasveta [241]
3 years ago
7

How many carbon are contained 25.00 g of sugar (C12H22O11)

Chemistry
1 answer:
zaharov [31]3 years ago
7 0
342 gm sugar = 1 mol of sugar = 12 moles of C. Therefore 25 gm of sugar will form = 25x12/342 = 0.877 moles of C. Therefore number of carbon atoms = number of moles x 6.02x 10^23 = 0.877x 6.02x 10^23 = 5.28x10^23.
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Statement 2 is correct.
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The water does not change it's H2O chemical makeup because salt was dissolved into it.
5 0
3 years ago
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The organic compounds that are divided into two types, simple and complex, are called _____.
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6 0
1 year ago
Calculate the standard enthalpy of formation of NOCl(g) at 25 ºC, knowing that the standard enthalpy of formation of NO(g) at th
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Answer:

The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol

Explanation:

The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:

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In this case, you have:  2 NOCl(g) → 2 NO(g) + Cl₂(g)

So, ΔH=2*H_{NO} +H_{Cl_{2} }-2*H_{NOCl}

Knowing:

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Replacing:

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Solving

-H_{NOCl}=75.5 kJ/mol - 2*90.25 kJ/mol

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H_{NOCl}=105 kJ/mol

<u><em>The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol</em></u>

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Answer:

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