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3 years ago

Describe the relationship between an enzyme, substrate, and active site.

1 answer:

8 0

So what I know is that enzyme and substrate are like lock and key meaning that when the active site of the enzyme changes, the enzyme will not fit to the substrate which will lead the enzyme to denature. Hope this helps.

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Plz help i’m gonna cry i’m in class rn

iragen [17]

Answer:

if ur gonna cry then just dont cry its simple logic guyss!!!!!!!!!!!!

Explanation:

3 0

3 years ago

A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula

Sever21 [200]

Answer:

Na₂CO₃•H₂O

Explanation:

After it is heated, the remaining mass is the mass of sodium carbonate.

30.2 g Na₂CO₃

Mass is conserved, so the difference is the mass of the water:

35.4 g − 30.2 g = 5.2 g H₂O

Convert masses to moles:

30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃

5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O

Normalize by dividing by the smallest:

0.285 / 0.285 = 1.00 mol Na₂CO₃

0.289 / 0.285 = 1.01 mol H₂O

The ratio is approximately 1:1. So the formula of the hydrate is Na₂CO₃•H₂O.

3 0

3 years ago

Read 2 more answers

1. A given mass of air has a volume of 6.00 L at 80.0°C. At constant pressure, the temperature is

earnstyle [38]

3 L will be the final volume for the gas as per Charle's law.

Answer:

Explanation:

The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.

V∝ T

Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be

$\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }$

So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.

$\frac{6}{80}=\frac{V_{2} }{40}$

$V_{2}=\frac{6*40}{80}=3 L$

So, 3 L will be the final volume for the gas as per Charle's law.

4 0

3 years ago

Aluminum has a density of 2.7 g/cm3. If a chunk of aluminum with a mass of 10.8 g is placed in a graduated cylinder partially fi

alisha [4.7K]

The water level that will rise is 4 cm^3

calculation

if the density i s 2.7 g/cm^3 this implies that

1cm^3 = 2.7 g
? = 10.8 g

by cross multiplication

(1 cm^3 x 10. 8 g) /2.7 g = 4 CM^3

6 0

3 years ago

Read 2 more answers

Write the formula of calcium oxide

8_murik_8 [283]

Answer:

calcium oxide CaO

hope it helps

7 0

2 years ago

Read 2 more answers