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ELEN [110]
3 years ago
5

Metallic tantalum crystallizes in a body-centered cubic lattice, with one Ta atom per lattice point. If the edge length of the u

nit cell is found to be 328 pm, what is the metallic radius of Ta in pm
Chemistry
1 answer:
LiRa [457]3 years ago
8 0

Answer:

The radius of the atom Ta is 142pm

Explanation:

To solve this question we need to know that for a body-centered cubic lattice we have the equations:

X = 4/√3 R

<em>Where X is edge length and R is radius of the atom in the lattice.</em>

<em />

If adge length of unit cell is 328 pm:

328pm = 4/√3 R

328pm * √3 / 4 = R

142pm = R

The radius of the atom Ta is 142pm

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Answer:

The options are unclear, however, the correct option is:

Aqueous solutions of ionic compounds cause to dissociate, hence, ions are free to conduct electricity

Explanation:

Ionic compounds are compounds formed from ions (charged atoms). For example, NaCl is an ionic compound from the following ions; Na+ (cation) and Cl- (anion). One characteristics of ionic compounds is their ability to dissociate into the ions that form them when in an aqueous solution i.e. NaCl will dissociate into Na+ and Cl- when in an aqueous solution.

These disssociated ions are free to conduct electricity, hence, making ionic compounds good conductors of electricity.

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Answer:

Strong acid breaks up into ions

Explanation:

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Consider the solubilities of a particular solute at two different temperatures.
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Explanation:

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4 0
2 years ago
Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the
Sergio [31]

Answer:

1.2\times 10^{-2}

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq)     K_3 = 1.89\times 10^{-10}

AgCl(aq)⇌Ag+(aq)+Cl−(aq)           K_4 = 1.25\times 10^{-4}

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

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4 0
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