The dissociation of acetic acid in water can be written as:
CH₃COOH + H₂O ↔ CH₃COO⁻ + H₃O⁺
The proton donor is CH₃COOH
The proton acceptor is H₂O
The acid is CH₃COOH
The conjugate base is CH₃COO⁻
Answer:
False
Explanation:
Half life is the time period at which the concentration of the radioactive substance in decay reduced to half.
<u>Thus, if the hydrogen-3 has gone 2 half lives, it means that it has first reduced to its half and then again the half of what it was, i.e. 1/4</u>
Thus, after two successive half-lives, the concentration must be 1/4 of the initial concentration and hence, the statement is false.
The answer would be , True
The answer is 5 gold token from Chuck E. Cheese
<span>Mendeleev realized that the physical and chemical properties of elements were related to their atomic mass in a 'periodic' way, and arranged them so that groups of elements with similar properties fell into vertical columns in his table.
</span>Mendeleev rewrote each edition of Principles of Chemistry<span>, including all new scientific data-particularly confirmations of the periodic law-and reanalyzing difficulties that had arisen to hinder its confirmation (inert gases, radioactivity, radioactive and </span>rare-earth elements<span>)
</span>he wanted to prove that he was right.
