The book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine: TRUE
<h3>
What is the book value?</h3>
- Book value is the worth of an asset based on its balance sheet account balance in accounting.
- The value of an asset is determined by subtracting the asset's original cost from any depreciation, amortization, or impairment expenses.
- Traditionally, a company's book value is equal to its total assets minus intangible assets and liabilities.
- In practice, however, depending on the source of the computation, book value may include either goodwill or intangible assets, or both.
- The value inherent in its employees, which is part of a company's intellectual capital, is always overlooked.
- When intangible assets and goodwill are specifically omitted, the indicator is frequently defined as "tangible book value."
Therefore, the statement "the book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine" is TRUE.
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Complete question:
The book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine. (Ignore taxes.) TRUE or FALSE
Answer:
c. 0.1 M Ga₂(SO₄)₃
Explanation:
The boiling point increasing of a solvent due the addition of a solute follows the formula:
ΔT = K*m*i
<em>Where K is boiling point increasing constant (Depends of the solute), m is molality = molarity when solvent is water, and i is Van't Hoff factor.</em>
<em />
That means the option with the higher m*i will be the solution with the highest boiling point:
a. NaCl has i = 2 (NaCl dissociates in Na⁺ and Cl⁻ ions).
m* i = 0.20*2 = 0.4
b. CaCl₂; i = 3. 3 ions.
m*i= 0.10M * 3 = 0.3
c. Ga₂(SO₄)₃ dissolves in 5 ions. i = 5
m*i = 0.10M*55 = 0.5
d. C₆H₁₂O₆ has i = 1:
m*i = 0.2M*1 = 0.2
The solution with highest boiling point is:
<h3>
c. 0.1 M Ga₂(SO₄)₃</h3>
Mg + 2HCl = H₂ + MgCl₂
n(HCl)=c(HCl)v(HCl)
n(H₂)=n(HCl)/2=c(HCl)v(HCl)/2
n(H₂)=3.0mol/L*0.2500L/2=0.375 mol≈0.38 mol
