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DedPeter [7]
3 years ago
7

How many moles of oxygen are needed to react with 23.8 moles of aluminum?

Chemistry
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

17.85moles

Explanation:

Check attachment

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When aluminium and chlorine compared , which has smaller atomic size ? Why ?​
Zielflug [23.3K]
Chlorine has a smaller atomic size.
Explanation: As you move towards right of the periodic table, the atomic size decreases. This is because the number of protons is increasing towards the right of the periodic table, which applies a greater inward force on the electrons. that is why the elements on the right of the periodic table have a smaller atomic size when compared to the elements on the left. Since chlorine is on the right side of aluminium, it has a smaller atomic size.
7 0
2 years ago
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Which laws can be combined to form the ideal gas law?
Morgarella [4.7K]
Answer: Charles's law, Avogadro's law and Boyle's law.

Justification:

Boyle's law states that at constant temperature  PV = constant

Charles law states that at constant pressure V/T = constant

Avogadro's law states that at constant pressure ant temperature, equal volume of gases contain equal number of moles: V/n = constant

Ideal gas law states PV/nT = constant => PV = nT*constant = PV = nTR
7 0
3 years ago
In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign
zloy xaker [14]

Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

                     k = Boltzmann constant

                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

               v_{rms} = \sqrt{\frac{3kT}{M}}

                            = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}

                            = 498.5 m/s

Hence, v_{rms} for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its v_{rms} speed as follows.

                v_{rms} = \sqrt{\frac{3kT}{M}}

                              = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}

                              = 524.5 m/s

Therefore, v_{rms} speed for nitrogen is 524.5 m/s.

3 0
3 years ago
Round to 4 significant figures.<br> 35.5450
Lelu [443]
Answer:
35.5450 will be rounded to 35.55
Explanation:
=35.5450
if the last digit is less than 5 then it will be ignored
=35.545
when the dropping digit is 5 then the retaining digit will increse by a factor of 1
=35.55
i hope this will help you
3 0
3 years ago
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What is the percent composition by mass of sulfur in the compound MgSO4 (gram formula mass = 120 g/mol)?
slavikrds [6]

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate. Explanation: Molar mass of compound = 120 g/mol.

7 0
2 years ago
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