Electric field between the plates of parallel plate capacitor is given as
here area of plates of capacitor is given as
also the maximum field strength is given as
now we will plug in all data to find the maximum possible charge on capacitor plates
so the maximum charge that plate will hold will be given by above
Answer:
,
Explanation:
The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:
where
k is the Coulomb constant
e is the magnitude of the charge of the electron
e is the magnitude of the charge of the proton in the nucleus
r is the distance between the electron and the nucleus
v is the speed of the electron
is the mass of the electron
Solving for v, we find
Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately
while the electron mass is
and the charge is
Substituting into the formula, we find
Answer:
If the acceleration is constant, the movements equations are:
a(t) = A.
for the velocity we can integrate over time:
v(t) = A*t + v0
where v0 is a constant of integration (the initial velocity), for the distance traveled between t = 0 units and t = 10 units, we can solve the integral:
Where to obtain the actual distance you can replace the constant acceleration A and the initial velocity v0.