Answer:
Three long wires are connected to a meter stick and hang down freely. Wire 1 hangs from the 50-cm mark at the center of the meter stick and carries 1.50 A of current upward. Wire 2 hangs from the 70-cm mark and carries 4.00 A of current downward. Wire 3 is to be attached to the meterstick and to carry a specific current, and we want to attach it at a location that results ineach wire experiencing no net force.
(a) Determine the position of wire 3.
b) Determine the magnitude and direction of current in wire 3
Explanation:
a) 

position of wire = 50 - 1.2
= 48.8cm
b) 

Direction ⇒ downward
Answer: - 452.088joule
Explanation:
Given the following :
Mass of water = 12g
Change in temperature(Dt) = (11 - 20)°C = - 9°C
Specific heats capacity of water(c) = 4.186j/g°C
Q = mcDt
Where Q = quantity of heat
Q = 12g × 4.186j/g°C × - 9°C
Q = - 452.088joule
If a proton were added to the nucleus of an atom . . .
-- It would become a different atom (an atom of a different element)
.
-- It would add 1 to the atomic mass.
-- Its charge would increase by +1
.
Answer:
58.9 N
Explanation:
The wood is buoyed up by the mass of the water is displaces
wood volume = .030 m^3 = 30 000 cm^3
mass of water displaced = 30 000 g = 30 kg
wood mass = 800 kg/m^3 * .030 m^3 = 24 kg
so tension in string = mg = ( 30 kg - 24 kg) * 9.81 m/s^2 = 58.9 N