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raketka [301]
3 years ago
9

Partially correct answer iconYour answer is partially correct. A proton initially has and then 2.30 s later has (in meters per s

econd).
(a) For that 2.30 s, what is the proton's average acceleration in unit vector notation,
(b) in magnitude, and
(c) the angle between and the positive direction of the x axis

Physics
1 answer:
morpeh [17]3 years ago
7 0

Answer: The question has some missing details. The initial velocity given as u = -6.5i + 17j + 13k and the final velocity v = -2.8i + 17j -9.3k.

a) = (1.82i - 9.69k)m/s2

b) magnitude = 9.85m/s2

c) direction = 280.64 degree

Explanation:

The detailed and step is shown in the attachment.

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The electric potential at the origin of an xy-coordinate system is 40 V. A -8.0-μC charge is brought from x = +∞ to that point.
vredina [299]

Answer:

-320 μJ.

Explanation:

Consider a point with an electrical charge of q. Assume that V is the electrical potential at the position of that charge. The electrical potential of that point charge will be equal to:

\text{Potential Energy} = q \cdot V.

Keep in mind that since both q and V might not be positive, the size of the electrical potential energy might not be positive, either.

For this point charge,

  • q = \rm -8.0\; \mu C; (that's -8.0 microjoules, which equals to \rm -8.0\times 10^{-6}\; J)
  • V = \rm 40\; V.

Hence its electrical potential energy:

\text{Potential Energy} = q\cdot V = \rm (-8.0\; \mu C) \times 40\; V = -320\; \mu J.

Why is this value negative? The electrical potential energy of a charge is equal to the work needed to bring that charge from infinitely far away all the way to its current position. Also, negative charges are attracted towards regions of high electrical potential. Bringing this \rm -8.0\; \mu C negative charge to the origin will not require any external work. Instead, this process will release 320 μJ of energy. As a result, the electrical potential energy is a negative value.

7 0
3 years ago
Why is the contribution of the wavelets lying on the back of secondary wave front zero?​
Tresset [83]

Answer:

The contribution of the wavelets lying on the back of the wave front is zero because of something known as the Obliquity Factor. It is assumed that the amplitude of the secondary wavelets is not independent of the direction of propagation, Sources: byju's.com

3 0
2 years ago
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A person walks 4.0 kilometers north, then 4.0 kilometers west. His displacement is closest to
larisa86 [58]
Use the Pythagoras for the magnitude and the tan^-1 x = -1 for the angle

displacement = 4^2 + 4^2 = 32 = 4 sqrt(2) =  5.65 km

angle is 135 degrees.

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Which is NOT a part of the Kinetic Molecular Theory? A) Atoms are in constant motion B) Gases are more compressible than liquids
djverab [1.8K]
The best answer would be the second option B) because that is NOT part of the Kinetic Molecular Theory.
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Describe how you determine whether an object is in motion
Flauer [41]
An object is in motion when its distance from another object is changing.
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