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raketka [301]
3 years ago
9

Partially correct answer iconYour answer is partially correct. A proton initially has and then 2.30 s later has (in meters per s

econd).
(a) For that 2.30 s, what is the proton's average acceleration in unit vector notation,
(b) in magnitude, and
(c) the angle between and the positive direction of the x axis

Physics
1 answer:
morpeh [17]3 years ago
7 0

Answer: The question has some missing details. The initial velocity given as u = -6.5i + 17j + 13k and the final velocity v = -2.8i + 17j -9.3k.

a) = (1.82i - 9.69k)m/s2

b) magnitude = 9.85m/s2

c) direction = 280.64 degree

Explanation:

The detailed and step is shown in the attachment.

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<u>Explanation:</u>

Given:

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The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

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The above equation can be written as below to find acceleration,

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Now. Substitute the given values, we get,

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