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Vanyuwa [196]
3 years ago
8

A car with a mass of 1500 kg is traveling down the interstate at 25 m/s. What is the kinetic energy of the car, measured in Joul

es?​
Physics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

The answer is

<h2>468 , 750 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}

where

m is the mass of the object

v is the speed or velocity

From the question

m = 1500 kg

v = 25 m/s

The kinetic energy of the object is

KE =   \frac{1}{2}  \times 1500 \times  {25}^{2}  \\  = 750 \times 625

We have the final answer

<h3>468 , 750 J</h3>

Hope this helps you

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A carpenter builds an exterior house wall with a layer of wood 3.0 cm thick on the outside and a layer of Styrofoam insulation 2
Leno4ka [110]

Answer:

A. T=15.54 °C

B. Q/A= 0.119 W/m2

Explanation:

To solve this problem we need to use the Fourier's law for thermal conduction:

Q= kA\frac{dT}{dx}

Here, the rate of flow per square meter must be the same through the complete wall. Therefore, we can use it to find the temperature at the plane where the wood meets the Styrofoam as follows:

\frac{Q}{A} =\frac{T_1-T_0}{d_w}k_w=\frac{T_2-T_1}{d_s}k_s\\T_1(\frac{k_w}{d_w}+\frac{k_s}{d_s})=T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}\\T_1=\frac{T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}}{\frac{k_w}{d_w}+\frac{k_s}{d_s}}\\T_1= 15.54 \°C

Then, to find the rate of heat flow per square meter, we have:

\frac{Q}{A}=\frac{T_1-T_0}{d_w}k_w=0.119 \frac{W}{m^2}\\\frac{Q}{A}=\frac{T_2-T_1}{d_s}k_s= 0.119 \frac{W}{m^2}

T_0: Temperature \ in \ the \ house\\T_1: Temperature \ at \ the \ plane \ between \ wood \ and \ styrofoam\\T_2: Temperature \ outside\\k_w: k \ for \ wood\\d_w: wood \ thickness\\k_s: k \ for \ styrofoam\\d_s: styrofoam \ thickness

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3 years ago
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