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Debora [2.8K]
3 years ago
6

When a gun is fired at the shooting range, the gun recoils (moves backward). Explain this using the law of conservation of momen

tum
Physics
1 answer:
12345 [234]3 years ago
4 0
The total momentum is unchanged according to the law of conservation of momentum. When the gun is fired, the bullet gains a high velocity forward (positive velocity), and that velocity multiplied by its mass is the momentum the bullet gains. Therefore, the gun must gain a momentum backwards to cancel out that momentum forward, so the gun recoils back with a negative velocity.
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A cosmic-ray proton in interstellar space has an energy of 59 MeV and executes a circular orbit with a radius equal to that of M
makkiz [27]

Answer:

Explanation:

Let mass and velocity of proton be m and v .

1/2 m v² = 59 x 10⁶ e V

= 59 x 10⁶ x 1.6 x 10⁻¹⁹ J

= 94.4 x 10⁻¹³ J

mv² = 188.8 x 10⁻¹³ J

v² =  188.8 x 10⁻¹³ / m

= 188.8 x 10⁻¹³ / 1.67262 x 10⁻²⁷

= 112.8768 x 10¹⁴

v = 10.62 x 10⁷ m / s

In circular path of proton , magnetic force equals centripetal force .

m v² / r = B q v , B is magnetic field , q is charge on proton , r is radius of circular path .

188.8 x 10⁻¹³ / 5.8 x 10¹⁰ = B x 1.6 x 10⁻¹⁹ x  10.62 x 10⁷

B = 1.9157 x 10⁻¹¹ T.

8 0
3 years ago
3. A 92 kg Tarzan is holding on to a level 22m vine. He swings on the vine. What will his speed at the bottom of the swing be?
insens350 [35]

To solve this problem, we must always remember that energy is conserved. In this case, since he is falling down, he has highest potential energy at the top and zero at bottom. While his kinetic energy is zero at the top since he started from rest and highest at the bottom. We can also say that Potential Energy lost is Kinetic Energy gained thus,

- ΔPE = ΔKE                         ---> one is negative since PE is losing energy

- m g (h2 – h1) = 0.5 m (v2^2 – v1^2)

Where,

m = mass of tarzan (cancel that out)

g = gravitational acceleration

h2 = height at the bottom= 0

h1 = height at top = 22 m

v2 = velocity at the bottom

v1 = velocity at top = 0 (started from rest)

Therefore substituting all values:

- 9.8 (- 22) = 0.5 (v2^2)

v2 = 20.77 m / s                 (ANSWER)

6 0
3 years ago
Set local ground level to 700 ft, and record the inches of mercury.
Katen [24]

The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

<h3>How to determine the altimeter reading?</h3>

The given parameters are:

  • Ground level = 700 ft i.e. the field elevation
  • Pressure altitude = 1450 ft

The pressure altitude is calculated as:

Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level

Substitute the known values

1450 = (29.92 - Altimeter reading) * 1000 + 700

Subtract 700 from both sides

750 = (29.92 - Altimeter reading) * 1000

Divide through by 1000

0.75 = 29.92 - Altimeter reading

Evaluate the like terms

Altimeter reading = 29.17

Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

Read more about pressure at:

brainly.com/question/26040104

#SPJ1

4 0
2 years ago
The heater element of a particular 120-V toaster is a 8.9-m length of nichrome wire, whose diameter is 0.86 mm. The resistivity
AleksAgata [21]

Answer:

Power, P = 722.96 watts

Explanation:

It is given that,

Voltage, V = 120 V

Length of nichrome wire, l = 8.9 m

Diameter of wire, d = 0.86 mm

Radius of wire, r = 0.43 mm = 0.00043 m

Resistivity of wire, \rho=1.3\times 10^{-6}\ \Omega-m

We need to find the power drawn by this heater. Power is given by :

P=\dfrac{V^2}{R}

And, R=\rho\dfrac{l}{A}

P=\dfrac{V^2\times A}{\rho\times l}

P=\dfrac{120^2\times \pi (0.00043)^2}{1.3\times 10^{-6}\times 8.9}

P = 722.96 watts

So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.    

3 0
3 years ago
its a hot day at the beach you look at your portable themometer which says its 30°C. what is the temperature in Fahrenheit and K
Nitella [24]

The answer is 86 degrees Fahrenheit.

Hope this helps :)

6 0
3 years ago
Read 2 more answers
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