Answer:
Explanation:
Let mass and velocity of proton be m and v .
1/2 m v² = 59 x 10⁶ e V
= 59 x 10⁶ x 1.6 x 10⁻¹⁹ J
= 94.4 x 10⁻¹³ J
mv² = 188.8 x 10⁻¹³ J
v² = 188.8 x 10⁻¹³ / m
= 188.8 x 10⁻¹³ / 1.67262 x 10⁻²⁷
= 112.8768 x 10¹⁴
v = 10.62 x 10⁷ m / s
In circular path of proton , magnetic force equals centripetal force .
m v² / r = B q v , B is magnetic field , q is charge on proton , r is radius of circular path .
188.8 x 10⁻¹³ / 5.8 x 10¹⁰ = B x 1.6 x 10⁻¹⁹ x 10.62 x 10⁷
B = 1.9157 x 10⁻¹¹ T.
To solve this problem, we must always remember that energy
is conserved. In this case, since he is falling down, he has highest potential
energy at the top and zero at bottom. While his kinetic energy is zero at the top
since he started from rest and highest at the bottom. We can also say that Potential
Energy lost is Kinetic Energy gained thus,
- ΔPE = ΔKE --->
one is negative since PE is losing energy
- m g (h2 – h1) = 0.5 m (v2^2 – v1^2)
Where,
m = mass of tarzan (cancel that out)
g = gravitational acceleration
h2 = height at the bottom= 0
h1 = height at top = 22 m
v2 = velocity at the bottom
v1 = velocity at top = 0 (started from rest)
Therefore substituting all values:
- 9.8 (- 22) = 0.5 (v2^2)
v2 = 20.77 m / s (ANSWER)
The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg
<h3>How to determine the
altimeter reading?</h3>
The given parameters are:
- Ground level = 700 ft i.e. the field elevation
- Pressure altitude = 1450 ft
The pressure altitude is calculated as:
Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level
Substitute the known values
1450 = (29.92 - Altimeter reading) * 1000 + 700
Subtract 700 from both sides
750 = (29.92 - Altimeter reading) * 1000
Divide through by 1000
0.75 = 29.92 - Altimeter reading
Evaluate the like terms
Altimeter reading = 29.17
Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg
Read more about pressure at:
brainly.com/question/26040104
#SPJ1
Answer:
Power, P = 722.96 watts
Explanation:
It is given that,
Voltage, V = 120 V
Length of nichrome wire, l = 8.9 m
Diameter of wire, d = 0.86 mm
Radius of wire, r = 0.43 mm = 0.00043 m
Resistivity of wire, 
We need to find the power drawn by this heater. Power is given by :

And, 


P = 722.96 watts
So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.