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Burka [1]
3 years ago
8

Witch unit is used to measure mass in the metric system

Physics
2 answers:
SOVA2 [1]3 years ago
7 0
Gram [g]

An uncommonly used unit of mass:

Centi-gram [cg]

Kilo-gram [kg]

Hope this helped ;)
Alecsey [184]3 years ago
6 0
The gram (g)
a nickel weighs 5 grams, and a raisin weighs approximately 1 gram.
There is also the kilogram(kg), or 1000 grams
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A fire breaks out and increases the Kelvin temperature of a cylinder of compressed gas by a factor of 2.4. What is the final pre
kherson [118]

Answer:

P(final) is 2.4 times P(initial).

Explanation:

Here we can assume that the cylinder did not break and it's volume and number of moles of gas present in the cylinder remains constant.

Given the temperature increases by a factor of 2.4. Let us assume that the initial temperature be T_{1} and the final temperature be T_{2}.

Given that T_{2}=2.4\times T_{1}

Now we know the ideal gas equation is PV=nRT

here V=constant , n=constant , R=gas constant(which is constant).

\frac{P}{T}=constant

\frac{P_{1} }{T_{1}}=\frac{P_{2} }{T_{2} }

P_{2}=(\frac{T_{2} }{T_{1} } )P_{1}

P_{2}=(\frac{2.4T_{1} }{T_{1} } )P_{1}

P_{2}=2.4\times P_{1}

7 0
3 years ago
Hi how do i run faster
Andrei [34K]

Answer:

Creatine is a great option , its not gonna help long term running ; but a great boost when you first start the run/jog.

Now to run faster you have to build great endurance and that is done through constant exercise running and stamina work outs such as sports , sprints calistetics etc.

Explanation:

Its not a simple 1 time thing and your suddenly , it takes drive and motivation !

Hope i was able to help you out ! Have a great day :)

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2 years ago
Help ASAP please & thank you ​
jasenka [17]

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7 0
3 years ago
Five difference between elastic collision and inelastic collision?​
olga_2 [115]

Answer:

Elastic Collision

Inelastic Collision

The total kinetic energy is conserved. The total kinetic energy of the bodies at the beginning and the end of the collision is different.

Momentum does not change. Momentum changes.

No conversion of energy takes place. Kinetic energy is changed into other energy such as sound or heat energy.

Highly unlikely in the real world as there is almost always a change in energy. This is the normal form of collision in the real world.

An example of this can be swinging balls or a spacecraft flying near a planet but not getting affected by its gravity in the end.

8 0
3 years ago
Two blocks, joined by a string, have masses of 6.0 and 9.0 kg. They rest on a frictionless, horizontal surface. A second string,
Lynna [10]

Answer:

T= 27 N

Explanation:

Assuming that the string joining both masses is massless  and inextensible, both masses accelerate at the same rate.

So, we can treat to both masses as a single system, and apply Newton's 2nd Law to both masses.

In this way, we can get the value of the acceleration without taking into account the tension in the string, as it is an internal force (actually a action-reaction pair).

Newton's 2nd law is a vector equation, so we can decompose the forces along perpendicular axis in order to convert it in two algebraic equations.

We can choose one axis as parallel to the horizontal surface (we call it x-axis, being the positive direction the one of  the movement of the blocks due to the horizontal force applied to the 6.0 kg block), and the other, perpendicular to it, so it is vertical (we call y-axis, being the upward direction the positive one).

Taking into account the forces acting  on both masses, we can write both equations as follows:

Fy = N- (m₁+m₂)*g = 0 (as there is no movement in the vertical direction)

Fx = Fh = (m₁ + m₂) * a ⇒ 45 N = 15.0 kg * a

⇒ a = 45 N / 15.0 kg = 3 m/s²

Now, in order to get the value of the tension T, we can choose as our system, to any mass, and apply Newton's 2nd Law again.

If we choose to the mass of 6.0 kg, in the horizontal direction, there are two forces acting on it, in opposite directions: the  horizontal applied force of 45 N, and the tension in the string that join both masses.

The difference of both forces, must be equal to the mass (of this block only) times the acceleration, as follows:

F- T = m₂* a ⇒ 45 N - T = 6.0 kg * 3 m/s²

⇒ T = 45 N -18 N = 27 N

We could have arrived to the same result taking the 9.0 Kg as our system, as the only force acting in the horizontal direction is just the tension in the string that we are trying to find out, as follows:

F = m₁*a = 9.0 kg* 3 m/s² = 27 N

4 0
3 years ago
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