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Lera25 [3.4K]
3 years ago
12

Calculate the impulse of a 0.140 kg baseball that starts at rest on a tee and reaches a final velocity of 20 m/s after being str

uck with a force of 100 N.
Physics
2 answers:
oee [108]3 years ago
5 0

Explanation:

<h2>impulse = change in momentum</h2><h2>F×t =m(v-u)</h2><h2>I = 0.140(20-0)</h2><h2>I = 0.140 × 20</h2><h2>I = 2.8NS</h2>
Nastasia [14]3 years ago
5 0

Answer: 2.8 Ns

Explanation:

Given that,

impulse I = ?

Mass of baseball M = 0.140 kg

Initial velocity (at rest) Vi = 0m/s

final velocity Vf = 20 m/s

force F = 100 N

Recall that impulse is the product of force and the time during which it acts

i.e Impulse = Force x Time

(since impulse is also equal to change in momentum, then

impulse = Ft = M x (Vf - Vi)

So, apply I = M x (Vf - Vi)

I = 0.140kg x (20 m/s - 0 m/s)

I = 0.140kg x (20 m/s)

I = 2.8 Ns

Thus, the impulse of the baseball is 2.8 Ns

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How much heat is needed to melt 13.74 kg of silver that is initially at 20°C?
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Answer:

Q = 4.63 \times 10^6 J

Explanation:

As we know that melting point of silver is

T = 961.8 degree C

Latent heat of fusion of silver is given as

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specific heat capacity of silver is given as

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now we will have

Q = ms\Delta T + mL

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\Delta T = 941.8 degree C

now from above equation

Q = (13.74)(240)(941.8) + (13.74)(111 \times 10^3)

Q = 3.1 \times 10^6 + 1.53 \times 10^6

Q = 4.63 \times 10^6 J

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