Answer:
Therefore 373 mole of Al produce 746 mole of water.
Explanation:
Given reaction is
3 Al+3NH₄ClO₄→Al₂O₃+AlCl₃+3NO+6H₂O
From the above reaction it is clear that 3 mole of Al produce 6 mole of water.
Therefore
3 mole of Al produce 6 mole of water.
1 mole of Al produce mole of water.
373 mole of Al produce mole of water.
= 746 mole of water.
Therefore 373 mole of Al produce 746 mole of water.
Answer:
Explanation:
The amount adsorbed (solute) is the acetic acid, and the adsorbent is the activated charcoal. The mass of the adsorbent is 10 g.
So, we need to calculate the mass of the acetic acid as follows:
Where:
n: is the number of moles = C*V
M: is the molecular mass = 60.052 g/mol
C: is the final concentration of the acid = 0.5*0.2 mol/L = 0.10 mol/L
V: is the volume = 50 ml = 0.050 L
Now, the amount of solute adsorbed per gram of the adsorbent is:
Therefore, the amount of solute adsorbed per gram of the adsorbent is 0.03 g/g.
I hope it helps you!