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Nimfa-mama [501]

4 years ago

11

The atom below with the greatest number of valence electrons is _______. A. Cl: 1S2 2S2 2P6 3S2 3P5 B. Br: 1S2 2S2 2P6 3S2 3P6 4

S2 3D10 4P5 C. I: 1S2 2S2 2P6 3S2 3P6 4S2 3D10 4P6 5S2 4D10 5P5 D. Ne: 1S2 2S2 2P6 E. None of the Above

1 answer:

allochka39001 [22]4 years ago

6 0

Me. It has 6 valence electrons. Everything else has 5

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En la electrosis del cloruro de sodio (Na Ci) el cloruro es atraido por elcatodo. Falso o verdadero. Y porque?

hram777 [196]

Answer:

Falso

Explanation:

La electrólisis es la descomposición de una solución cuando la corriente continua se pasa a través de ella.

La corriente entra y abandona el electrolito a través de los electrodos. El electrodo positivo se llama el ánodo mientras el electrodo negativo se llama cátodo.

Los iones positivos se mueven hacia el cátodo, mientras que los iones negativos se mueven hacia el ánodo.

Dado que el cloruro es un ion negativo, se mueve hacia el ánodo y no hacia el cátodo.

8 0

3 years ago

How many moles are in 2.12g Cr2O3

ohaa [14]

Answer:

0.01395mol Cr2O3

Explanation:

the molar mass of Cr2O3 is 151.9904 g/mol

2.12g Cr2O3 x 1 mol/151.9904g = 0.01395mol Cr2O3

4 0

3 years ago

If a system has a reaction quotient of 2.13 ✕ 10−15 at 100°C, what will happen to the concentrations of COBr2, CO, and Br2 as th

qaws [65]

This is an incomplete question, here is a complete question.

Consider the following equilibrium at 100°C.

$COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)$

$K_c=4.74\times 10^4$

Concentration at equilibrium:

$[COBr_2]=1.58\times 10^{-6}M$

$[Co]=2.78\times 10^{-3}M$

$[Br_2]=2.51\times 10^{-5}M$

If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?

Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

$COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)$

The expression for reaction quotient will be :

$Q=\frac{[CO][Br_2]}{[COBr_2]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}$

The given equilibrium constant value is, $K_c=4.74\times 10^4$

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When $Q>K_c$ that means product > reactant. So, the reaction is reactant favored.

When $Q$ that means reactant > product. So, the reaction is product favored.

When $Q=K_c$ that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the $Q$ that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.

Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

3 0

3 years ago

How many unpaired electrons in ge.

marshall27 [118]

Answer:

Ge only has 2 pair of unpaired electrons.

Explanation:

4 0

3 years ago

A student is adding DI water to a volumetric flask to make a 50% solution. Unfortunately, he was not paying attention and filled

dalvyx [7]

Answer:

His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.

Explanation:

The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.

Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.

Suppose the mass of the solute is m.

Originally, the density is = $\frac{m}{50}$ $\left(\frac{\text{mass}}{\text{volume}}\right)$

Now after adding extra 10 mL , the density becomes $\frac{m}{60}$ .

Therefore, $\frac{m}{50}>\frac{m}{60}$

So the density decreases when we add more solution.

4 0

3 years ago