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2 years ago

Answer these multiple choice questions!!! 20 points!!!

Physics

2 answers:

irga5000 [103]2 years ago

7 0

I need pictures or something

uysha [10]2 years ago

5 0

Top one ... A

Bottom one ... B

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These two waves travel along the same string: y1 = (4.17 mm) sin(2.24?x - 300?t), y2 = (5.96 mm) sin(2.24?x - 300?t + 0.727?rad)

Luba_88 [7]

Answer:

a) Amplitude is 9.49 mm

b) ∅ = 0.43056 rad = 24.7°

c) phase angle = 2.24x - 300t + 0.43056 rad

Explanation:

Given that;

A1 = y1 = (4.17 mm) sin(2.24x - 300t)

A2 = y2 = (5.96 mm) sin(2.24x - 300t + 0.727rad)

now phase difference between y1 and y2 is;

Δ∅ = (2.24x - 300t + 0.727rad) - (2.24x - 300t) = 0.727 rad = 41.65°

a) the amplitude

Amplitude A = √( A1² + A2² + 2A1A2cosΔ∅)

we substitute

A = √( (4.17)² + (5.96)² + (2 × 4.17 × 5.96 × cos(41.65) )

A = √( 17.3889 + 35.5216 + ( 49.7064 × 0.7472 )

A = √(52.9105 + 37.1406 )

A = √90.0511

A = 9.49 mm

Therefore, Amplitude is 9.49 mm

b) the phase angle (relative to wave 1) of the resultant wave;

tan∅ = A2sinΔ∅ / ( A1 + A2cosΔ∅)

we substitute

tan∅ = 5.96sin41.65 / ( 4.17 + 5.96cos41.65)

tan∅ = 3.96088 / ( 4.17 + 4.4534)

tan∅ = 3.96088 / 8.6234

tan∅ = 0.4593

∅ = tan⁻¹ ( 0.4593 )

∅ = 0.43056 rad = 24.7°

For the third wave, maximum amplitude. it should be in the direction of resultant of A1 and A2

so, phase angle in order to maximize the amplitude of the new resultant wave will be;

phase angle = 2.24x - 300t + 0.43056 rad

6 0

2 years ago

In the previous question, the person had an initial velocity of 8m/s and a constant acceleration of −4m/s2. How would the maximu

oksian1 [2.3K]

Answer:

Distance maximum

Xmax = 32m

Explanation:

Kinematics equation between velocities and distance:

$Vf^{2} =Vo^{2} +2ax$

For the distance maximum the final velocity is zero:

$x = Xmax$ ⇒ $Vf=0$

then, the equation becomes:

$Xmax= - \frac{Vo^{2}}{2a}$

We replace the values for the initial velocity and acceleration

Vo=16m/s; a = -4m/s2

Finally:

$Xmax=16^{2} /8=32m$

5 0

3 years ago

The work done to lift a 10kg object to a height of 1m above the ground is

vlada-n [284]

A = mg∆h = 10•10•1 = 100J

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3 years ago

A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 = 18 V and V2 = 12 V. The po

kaheart [24]

The I3 will be 158 A.

<h3>How to find the current through the circuit?</h3>

The foundation of circuit analysis is Kirchhoff's circuit laws.
We have the fundamental instrument to begin studying circuits with the use of these principles and the equation for each individual component (resistor, capacitor, and inductor).
These rules aid in calculating the current flow in various network streams as well as the electrical resistance of a complicated network, or impedance in the case of AC.

To calculate I3 firstly, V4 has to be calculated,

$V_{4} =I_{4} R_{4}$