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3 years ago

Answer these multiple choice questions!!! 20 points!!!

Physics

2 answers:

irga5000 [103]3 years ago

7 0

I need pictures or something

uysha [10]3 years ago

5 0

Top one ... A

Bottom one ... B

You might be interested in

Air pressure decreases as

bearhunter [10]

The answer is going to be B: elevation.

8 0

3 years ago

At the Earth's surface, a projectile is launched straight up at a speed of 10.0km / s. To what height will it rise? Ignore air r

icang [17]

At h = 5199.28 km it will rise. Kinetic energy is a type of energy that is present in a particle or object in motion.

<h3>What is kinetic energy?</h3>

Kinetic energy is a type of energy that is present in a particle or object in motion. When work, which entails the transfer of energy, is done on an object by applying a net force, that object acquires kinetic energy.

There are five types of kinetic energy: mechanical, electrical, acoustic, thermal, and radiant. Kinetic energy (KE), which is the energy of a body in motion, is essentially the energy of all moving objects. It is one of the two main types of energy together with potential energy, which is the stored energy existing in objects at rest.

<h3>To what height will it rise?</h3>

Equating the initial kinetic energy to the final potential energy

At the highest point, the body has only potential energy

initial kinetic energy = .5 * m * v2

velocity = 10.1 km/s

= 10.1 * 10100 m/s

= 10100 m/s

KE = .5 * m * (10100)2 = 51.005 x 106 x m J

potential energy = m x g x h

max height reached = m x 9.81 x h

m x 9.81 x h = 51.005 x 106 x m J

h = 5199.28 km

To learn more about kinetic energy, refer to:

brainly.com/question/25959744

#SPJ4

6 0

1 year ago

1. On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the t

Ira Lisetskai [31]

Answer:

a) $f_{e}$ = 3,375 cm , b) f₀ = 77.625 cm

Explanation:

The magnification of a telescope is, to see at the far point of vision (infinity image)

m = - f₀ / $f_{e}$

The length of the tube is

L = f₀ + $f_{e}$

a) The focal length of the eyepiece

L = - m $f_{e}$ + $f_{e}$

L = $f_{e}$ (1-m)

$f_{e}$ = L / (1-m)

Let's calculate

$f_{e}$ = 81.0 / (1 - (-23.0)

$f_{e}$ = 3,375 cm

b) the focal length of the target

f₀ = -m $f_{e}$

f₀ = 23 (3.68)

f₀ = 77.625 cm

8 0

3 years ago

A vertical spring with a spring constant of 420 N/m is mounted on the floor. From directly above the spring, which is unstrained

mixas84 [53]

Answer:

19.53 cm

Explanation:

The computation of the height is as follows:

Here we applied the conservation of the energy formula

As we know that

P.E of the block = P.E of the spring

m g h = ( 1 ÷ 2) k x^2

where

m = 0.15

g = 9.81

k = 420

x = 0.037

So now put the values to the above formula

(0.15) (9.81) (h) = 1 ÷2 × 420 × (0.037)^2

1.4715 (h) = 0.28749

h = 0.19537 m

= 19.53 cm

3 0

3 years ago

A source emits sound uniformly in all directions. There are no reflections of the sound. At a distance of 12 m from the source,

yaroslaw [1]

Answer:

1.58 W

Explanation:

Since the sound spreads uniformly in all directions, it must be in a form of a circle with radius of 12 m. So the area of the circle is

$A = \pi r^2 = \pi 12^2 = 452.389 m^2$

From the intensity of the sound we can calculate the power at 12 m

$P = AI = 452.389 * 3.5\times10^{-3} = 1.58 W$

7 0

3 years ago