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Rudik [331]
3 years ago
9

What happens when you rub an ebonite stick with a wool cloth?

Physics
2 answers:
Margarita [4]3 years ago
7 0
That procedure produces several effects. Perhaps the most noticeable one is that the ebonite stick becomes clean and shiny.
Alchen [17]3 years ago
4 0
It is called static electricity...

electrical nature of matter

the stick become deficient in electrons and said to be positively charge. The wool having gained the electrons lost by the rod, has an excess of electrons and becomes negatively charge.
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Which property of a body resists change from a state of rest or of motion?
jeyben [28]

Answer:

mass

Explanation:

As this is directly related to inertia. Inertia is the property of unit which resists the change of state of rest or motion

7 0
2 years ago
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Why do wisdom teeth appear later than other types of teeth?
alexandr402 [8]
Hey there!


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3 0
3 years ago
Find the unknown mass of the block 1 needed to balance the bar. Assume that the mass of the bar is negligible. Block 1 is locate
Natasha2012 [34]

Answer:

Incomplete question: The masses of the blocks m₂ = 1.5 kg and m₃ = 2 kg

Explanation:

Given data:

L₁ = length = 0.85 m

L₂ = 0.25 m

L₃ = 0.5 m

m₂ = 1.5 kg

m₃ = 2 kg

Question: Find the unknown mass of the block 1 needed to balance the bar, m₁ = ?

The torque is zero (intermediate point of the bar)

-m_{1} gL_{1} +m_{2} gL_{2} +m_{3} gL_{3} =0

Is negative because mass 1 is to the left of the coordinate system (see the diagram)

m_{1} =\frac{m_{2} gL_{2}+m_{3} gL_{3}  }{L_{1} } =\frac{(1.5*0.25)+(2*0.5)}{0.85} =1.6176kg

4 0
4 years ago
True or False. The wavelength (of a sinusoidal wave) is the distance from one crest to the next crest.​
Irina-Kira [14]

Answer:

true

Explanation:

3 0
3 years ago
The length of a certain wire is doubled and at the same time its radius is also doubled. What is the new resistance of this wire
Leto [7]

Answer:

R' = R/2

Therefore, the new resistance of the wire is twice the value of the initial resistance.

Explanation:

Consider a wire with:

Resistance = R

Length = L

Area = A = πr²

where, r = radius

ρ = resistivity

Then:

R = ρL/A

R = ρL/πr²   --------------- equation 1

Now, the new wire has:

Resistance = R'

Resistivity = ρ

Length = L' = 2 L

Radius = r' = 2r

Area = πr'² = π(2r)² = 4πr²

Therefore,

R' = ρL'/πr'²

R' = ρ(2 L)/4πr²

R' = (1/2)(ρL/πr²)

using equation 1:

<u>R' = R/2</u>

<u>Therefore, the new resistance of the wire is twice the value of the initial resistance.</u>

4 0
3 years ago
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