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Finger [1]
3 years ago
13

Why does atomic radius decrease from left to right?

Physics
1 answer:
victus00 [196]3 years ago
7 0
Because the effective charge of the nucleus increase from left to eight due to the increasing number of protons.

The greater charge pulls the electrons closer to the nucleus, decreasing the radius.
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What is Newton's 2nd law of motion? *<br> Your answer
Novay_Z [31]
Acceleration of an object is depended upon the net force acting open the object and the mass of the object
4 0
3 years ago
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In physics, why would an equation like y=mx+b be plotted as a straight line rather than as a parabola, as is done in math?
notka56 [123]

Answer:

Explanation:

In Both Physics and Math

y=mx+b is plotted as straight line where

m=slope of line

b=intercept on Y-axis

whereas Equation of parabola is something like this

y^2=4ax

or

x^2=4ay

Math is a tool to solve Physics problems so equations are same in math and physics

3 0
3 years ago
friction force is the opposition to the motion of surfaces sliding across each other. what is one factor that affects the amount
ruslelena [56]

Answer

Nature of the surfaces.


Explanation

Friction is the the force that opposes motion between two surfaces that are in relative motion. If two objects are in contact, one of it or both must be in motion for friction to exist.

Friction is affected by a number of factors.

One is the weight of the object. The more the weight of the object the higher the friction between it and the surface.

The other factor is the nature of the surfaces. Rough surfaces contribute to high friction while smooth surfaces reduces the friction between surfaces.  

3 0
3 years ago
His eyes are 1.64 m above the floor and the top of his head is 0.14 m higher. Find the height (in m) above the floor of the top
Aloiza [94]

Answer:

Height above the floor from the bottom is 0.82m

Form the top is 1.71m

Explanation:

See attached file

3 0
3 years ago
A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. Wha
Gwar [14]

A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. The change in the electric potential energy of the proton-field system when the proton travels to x = 2.50m is -3.40 × 10⁻¹⁶ J (Option B)

<h3 /><h3>How is the change in electric potential energy of the proton-field system calculated?</h3>

  • Work done on the proton =Negative of the change in the electric potential energy of the proton field
  • In the given case, W = -qΔV
  • -W = qΔV
  • = qEcosθ
  • Therefore, work done on the proton = -e(8.50×10^2 N/C)(2.5m)(1)
  • = -3.40×10^-^1^6 J
  • Any change in the potential energy indicates the work done by the proton.
  • Therefore the positive sign shows that the potential energy increases when the proton does the work.
  • The negative sign shows that the potential energy decreases when the proton does the work.

To learn more about electric potential energy, refer

brainly.com/question/14306881

#SPJ4

3 0
1 year ago
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