Question

airground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has an 11 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration 2.3 times that due to gravity

Answer 1

Answer:

N = 13.65 rpm

Explanation:

given data

radius = 11 m

centripetal acceleration =  2.3 times that due to gravity

to find out

how many revolutions per minute

solution

we know here centripetal accel = 2.3 × g

ω²r  = 2.3 × 9.8

ω² × 11  = 2.3 × 9.8  

solve it we get

ω² = 2.0490

ω = 1.43 rad/s

and

ω = $\frac{2\pi N}{60}$

1.43 = $\frac{2\pi N}{60}$  

solve it we get

N = 13.65 rpm