1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
allsm [11]
3 years ago
6

What particle decay is this? 210 83 Bi→210 84 Po ​

Chemistry
1 answer:
sesenic [268]3 years ago
3 0

Answer:

Beta emission

Explanation:

In beta emission, a neutron is converted into a proton thereby emitting an electron and a neutrino. A neutrino is a particle that serves to balance the spins.

When a nucleus undergoes beta emission, the mass number of the parent and daughter nuclei remain the same while the atomic number of the daughter nucleus is greater than that of its parent by one unit.

Hence, in beta emission, the daughter nucleus is found one pace to the right of the parent in the periodic table.

You might be interested in
All objects emit and absorb electromagnetic radiation.
olchik [2.2K]
All objects DO emit and absorb electromagnetic radiation. therefore, true.
8 0
2 years ago
1. Raw egg to boiled egg.
QveST [7]

Answer:

1.Irreversible

2.Physical

3.

6 0
3 years ago
A piece of wood that measures 2.7 cm x 5.5 cm x 3.9 cm has a mass of 84 g what is the density of the wood
Korolek [52]

The density of the wood : 1.45 g/cm³

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

  • Volume of the wood

\tt V=2.7\times 5.5\times 3.9=57.915~cm^3

  • density

\tt \rho=\dfrac{m}{V}\\\\\rho=\dfrac{84~g}{57.915~cm^3}=\boxed{\bold{1.45`g/cm^3}}

6 0
3 years ago
What is the edge length of a face-centered cubic unit cell made up of atoms having a radius of 144 pm?
belka [17]

Answer:

407pm is the edge length of the cubic unit cell

Explanation:

In a Face-centered cubic unit you can use Pythagoras theorem to relate edge length with atomic radius (As you can see in the picture), thus:

e²+e² = (4r)²

2e² = 16r²

e = √8 r

If the atomic radius of the atom is 144pm:

e = √8 ×144pm

e = 407ppm

407pm is the edge length of the cubic unit cell

8 0
3 years ago
does anyone know how to find the electron configuration of an element without using a periodic table?? group and period is alrea
snow_lady [41]
For that you have to use the Aufbau principle

For example, writing the electronic configuration of Fe(28)

I recommend that you memorize the aufbau principle. Once you learn it, you don’t need anything else except the atomic number of the element to write it’s electronic configuration.
8 0
2 years ago
Read 2 more answers
Other questions:
  • An object has a mass of 5 kg. What force is needed to accelerate it at 6 m/s2? (Formula: F=ma) 0.83 N 1.2 N 11 N 30 N
    6·2 answers
  • Why is it important for you to learn where the safety equipment is located in the lab?
    6·1 answer
  • What kind of charge does a cation have
    11·2 answers
  • Why are covalent bonds between hydrogen and nitrogen or oxygen polar? see section 2.1 ( page 57) ?
    7·1 answer
  • When traveling from oxygen to sulfur to selenium, through this group in the periodic table, what is changing?
    14·2 answers
  • The [H+] of a solution can be determined from the pH using the equation: [H+] = 10 - pH ... Where: [H+] = hydrogen ion concentra
    12·1 answer
  • Which temperature scale would read the highest number for boiling water? A. Kelvin B. Celsius C. Fahrenheit
    6·2 answers
  • How does the corona of the Sun affect earth
    6·2 answers
  • I need help please, will mark you the brainliest.
    15·1 answer
  • 5. How many moles are in 10g of sodium?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!