The reaction between methane gas and chlorine gas to form hydrogen chloride and carbon tetrachloride, all in their gaseous form can be expressed through the chemical reaction below.
CH₄ + 4Cl₂ --> 4HCl + CCl₄
Let us assume that all the involved gases behaves ideally such that each mole of the gas is equal to 22.4 L.
Through proper dimensional analysis, the volume of the produced hydrogen chloride is calculated,
V(HCl) = (1.69 mL CH₄)(1 L CH₄/ 1000 mL CH₄)(1 mol CH₄/22.4 L CH₄)(4 mols HCl/1 mol CH₄)(22.4 L HCl/1 mol HCl)(1000 mL/1 L)
V(HCl) = 6.76 mL
<em>ANSWER: 6.76 mL</em>
Answer: The answer is D. This has a Carboxylic Acid group, and is acetic acid, or Ethanoic Acid.
ALWAYS LOOK for the Functional Group in question.
A. Would likely not stay in water, or at least not be acidic, for it is butane gas.
B. Is 1-propanol, and alcohols are not acidic as a rule. Certainly not in water.
C. This is an Ether. It will not give up an H+, it it not an acid.
E. This functional group is an amine, which is more “base” like, since the lone pairs of the Nitrogen atom would tend to attract a H+.
A) occurs when water is evaporated.
Answer:
c = 1.61 j/g.°C
Explanation:
Given data:
Mass of oil = 9 g
Heat added = 824 j
Initial temperature = 30°C
Final temperature = 87°C
Specific heat of oil = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - final temperature
ΔT = 87°C - 30°C
ΔT = 57 °C
Q = m.c. ΔT
824 j = 9 g × c × 57 °C
824 j = 513 g. °C × c
c = 1.61 j/g.°C
