Answer:
Ans: 2
Explanation:
The concentration of reactants and the concentration of products are constant.
Answer:
Let's say we were Subtracting 3-2=? To Find the Answer we would Subtract 2 from 3 which is 1 Simple our answer is 1 But let's say the Question is 3 - 1= ? to find this answer we would subtract 1 from 3 which is 2 Let's say you were subtracting 3-3=? to do this we take 3 away from 3 now 3 is 0 so our answer is 0 so there are 3 different problems we can make with 3 we could make more but I'm just telling the basics Hope I Helped Bye :)
Explanation:
Answer:
3 g/mL
Explanation:
We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).
Formula
D=m/v
Given data:
Mass= 45 g
Volume= 15 mL
Now we will put the values in formula:
D=45 g/ 15 mL= 3 g/mL
Answer:
Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).
Explanation:
Hello there!
In this case, according to the given redox reaction, we rewrite it as a convenient first step:

Next, we assign the oxidation numbers as follows:

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).
Regards!
The energy required to break existing chemical bonds in reactants is called the activation energy.
<h3>What is activation energy?</h3>
Activation energy in chemistry is the energy required to initiate a chemical reaction.
Chemical reactions involve the breaking of chemical bonds in substances called reactants to form new substances called products.
The energy required to break the bond in the existing reactants thus elevating these substances to a state of high activation is known as activation energy.
Therefore, it can be said that energy required to break existing chemical bonds in reactants is called the activation energy.
Learn more about activation energy at: brainly.com/question/11334504
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