The electric field E of a charge is defined as E=F/Q where F is the Coulomb force and Q is the test charge.
E=(1/Q)*k*(q*Q)/r², where k=9*10^9 N*m²/C², q is the point charge, Q is the test charge and r is the distance between the charges.
So E=(k*q)/r²
When we input the numbers we get that electric field E of a point chage q is:
E=(9*10^9)*(5.4*10^-8)/0.2²=486/0.04=12150 N/C.
This is roughly E=12000 N/C =1.2*10^4 N/C
The correct answer is B.
2 is the answer have a nice day <3
<u>D: Half</u>
We know that,
F = m.a, where F is the force, m is the object's mass and a is the acceleration.
In the first case, we observed that a1 = F/m.
In the second case, we observed that the mass has been doubled, so a2 = F/2m .
By the ratio of the two cases, we get
a1/a2 = F/m / F/2m
or, a1/a2 = 2
or, a1 = 2.a2
or, a1/2 = a2
Therefore, the acceleration gets <u>half</u> of it's original measurement.
Elastic Potential Energy because the elasticity in the string stores up the energy.
Answer:
The work done is equal to zero = 0
Explanation:
Let us remember that the definition of physical work is given by the product of force by the displacement of the body.
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