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elixir [45]
1 year ago
13

A 60 year old person has a threshold of hearing of 79.0 dB for a sound with frequency f=10,000 Hz. By what factor must the inten

sity of a sound wave of that frequency, audible to a typical young adult, (sound level=43.0 dB) be increased so that it is heard by the older person.
Physics
1 answer:
liubo4ka [24]1 year ago
6 0

They provided the intensity in decibels for the problem, but they are unsure by what factor to increase it (I) to make the sound loud enough for the elderly person to hear.

Neglect f entirely.

The following equation must be used to convert decibels (dB) to I:

I=(10^(dB/10))*10^-12

Divide the elder person's dB by the younger person's dB after doing this for each dB.

After putting values and solving

we get,

1.8372093023.

So, the final answer is 1.8372093023.

learn more about frequency brainly.com/question/254161

#SPJ1

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A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total
Lynna [10]

Explanation:

Given Data

Total mass=93.5 kg

Rock mass=0.310 kg

Initially wagon speed=0.540 m/s

rock speed=16.5 m/s

To Find

The speed of the wagon

Solution

As the wagon rolls, momentum is given as

P=mv

where

m is mass

v is speed

put the values

P=93.5kg × 0.540 m/s

P =50.49 kg×m/s

Now we have to find the momentum of rock

momentum of rock = mv

momentum of rock = (0.310kg)×(16.5 m/s)

momentum of rock =5.115 kg×m/s  

From the conservation of momentum we can find the wagons momentum So

wagon momentum=50.49 -5.115 = 45.375 kg×m/s  

Speed of wagon = wagon momentum/(total mass-rock mass)

Speed of wagon=45.375/(93.5-0.310)

Speed of wagon= 0.487 m/s

Throwing rock backward,

momentum of wagon = 50.49+5.115 = 55.605  kg×m/s

Speed of wagon = wagon momentum/(total mass-rock mass)

speed of wagon = 55.605  kg×m/s/(93.5kg-0.310kg)

speed of wagon= 0.5967 m/s

7 0
3 years ago
A string attached to an airborne kite was maintained at an angle of 40.0 with the ground. if 120m of string was reeled in to ret
AleksAgata [21]
The hypotenuse is measured at 120 meters of string, and you need to solve for the leg of the triangle that is horizontal. The degree is 40, so use trigonometry to figure it out. 
Cosin (40) is equal to around .766 
Adjacent/Hypotenuse 
x/120 = cos40 
Answer: 91.92533. 
If you use 3 significant figures it should be 91.9 meters.
5 0
3 years ago
At the same moment from the top of a building 3.0 × 10 2 m tall, one rock is dropped and one is thrown downward with an initial
Bess [88]
The equation that relates distance, velocities, acceleration, and time is,
                   d = V₀t + 0.5gt²
where d is distance,
V₀ is the initial velocity,
t is time, and 
g is the acceleration due to gravity (equal to 9.8 m/s²)

(1) Dropped rock,
                  (3 x 10² m ) = 0(t) + 0.5(9.8 m/s²)(t²)
The value of t from this equation is 24.73 s

(2) Thrown rock with V₀ = 26 m/s
                (3 x 10² m) = (26)(t) + 0.5(9.8 m/s²)(t²)
The value of t from the equation is 5.61 s

The difference between the tim,
        difference = 24.73 s - 5.61 s
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<em>ANSWER: 19.12 s</em>
5 0
3 years ago
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A garden hose attached with a nozzle is used to fill a 10‐ gal bucket. The inner diameter of the hose is 2 cm, and it reduces to
nadya68 [22]

Answer:

Explanation:

Given

Volume of bucket V=10\ gallon

Time taken to fill the bucket t=50\ s

so volume flow rate is \dot{V}=\frac{10}{50}=0.2\ gal/s

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\dot{V}=0.0267\ ft^3/s

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(b)Average velocity through nozzle exit

\dot{V}=Av_{avg}

v_{avg}=\dfrac{0.0267}{\frac{\pi}{4}\times (0.0262)^2}

v_{avg}=49.51\ ft/s

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