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3 years ago

What determines whether or not work is being done?

1 answer:

3 0

C is the correct answer but the best possible answer is that work is done when a force is imposed on an object and the object moves in the same direction as the force

Hope this helps!

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Calculate the force of attraction between

vagabundo [1.1K]

Answer:

So the force of attraction between the two objects is 3.3365*10^-6

Explanation:

m1=10kg

m2=50kg

d=10cm=0.1m

G=6.673*10^-11Nm^2kg^2

We have to find the force of attraction between them

F=Gm1m2/d^2

F=6.673*10^-11*10*50/0.1^2

F=3.3365*10^-8/0.01

F=3.3365*10^-6

4 0

3 years ago

what does it mean for data to be reproducible? how would you conduct an experiment in such a way as to get data reproducible?

PIT_PIT [208]

Reproducible is the term where your answers are similar to other groups. If every other group has similar results as yours (only if you use the same measurements) your results are reproducible. If your results are different to every other group your results aren't reproducible. <span />

3 0

3 years ago

Read 2 more answers

What would be the current of the same wire if it was moved up towards the magnet instead of through the magnetic field?

Aleks04 [339]

Answer:

0 v

Explanation:

3 0

2 years ago

A skateboarder jumps horizontally off the top of a staircase and lands at bottom of the stairs. The staircase has a horizontal l

e-lub [12.9K]

Answer:

The vertical velocity of the skater upon landing is 10.788 meters per second.

Explanation:

Skateboarder experiments a parabolic movement. As skateboarder jumps horizontally off the top of the staircase, it means that vertical component of initial velocity is zero and accelerates by gravity, the final vertical speed is calculated by the following expression:

$v = v_{o} + g\cdot t$

Where:

$v_{o}$ - Initial vertical speed, measured in meters per second.

$v$ - Final vertical speed, measured in meters per second.

$g$ - Gravitational acceleration, measured in meters per square second.

$t$ - Time, measured in seconds.

Given that $v_{o} = 0\,\frac{m}{s}$ , $g = -9.807\,\frac{m}{s^{2}}$ and $t = 1.10\,s$ , the final velocity of the skater upon landing is:

$v = 0\,\frac{m}{s} + \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (1.10\,s)$

$v = -10.788\,\frac{m}{s}$

The vertical velocity of the skater upon landing is 10.788 meters per second.

3 0

3 years ago

A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turn

Cerrena [4.2K]

Answer:

e. Not enough information to determine

Explanation:

This question is incomplete. Here is the complete question with my solution afterwards;

A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.

What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)

a. The ladybug begins to slide

b. The gentleman bug begins to slide

c. Both bugs begin to slide at the same time

d. Nothing ever happens

e. Not enough information to determine

The centripetal force acting on a rotating body or bugs can be written as,

$F=mrw^2$

$m=$ mass of the corresponding bugs

$r=$ corresponding radial distance of each bug

$w=$ angular speed of the turntable

The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable

$F$ ∝ $mr$

Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.

Option "e" is correct.

7 0

3 years ago

Read 2 more answers