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lapo4ka [179]
3 years ago
9

A golf club with 65J of kinetic energy strikes a stationary golf ball with a mass of 46g. The energy transfer is only 20% effici

ent. Calculate the initial speed of the golf ball
Physics
1 answer:
umka21 [38]3 years ago
4 0
Kinetic energy of golf club = 65J, 
kinetic energy supplied to golf ball = 20% of 65 = 0.2 * 65 = 13J,
kinetic energy of ball = [mass * Velocity²]/2,
mass = 46gm = 0.046Kg,
[0.046 * V²]/2 = 13, or 0.046 *V² = 26, 
V² = 26/0.046 = 565.22, 
V = 23.77 m/sec = initial velocity of golf ball after hitting.
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Explanation:

Solution:

At 300K:

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σ = C x (M_{h} + M_{e}) e

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σ = 4.32 x 10^{-6}

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Resistivity = 1/ 4.32 x 10^{-6}

Resistivity = 231.481 K Ohm

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