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trasher [3.6K]
3 years ago
14

What is the boiling point of water?​

Chemistry
2 answers:
Nat2105 [25]3 years ago
8 0

Answer:

The boiling point of water is 212 degrees fahrenheit, and/or 100 degrees celsius.

ExtremeBDS [4]3 years ago
6 0

Answer:

212°F , 100°C , 373.15°K

They are all the same, in different units.

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The correct answer to this question is that the length of 14 is it’s half Which would be 7
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Given the reaction: solid sodium reacts with chlorine gas to form solid sodium chloride How many moles of the product result fro
lyudmila [28]

Answer:

number of moles of NaCl produce = 12 mol

Explanation:

Firstly, we need to write the chemical equation of the reaction and balance it .

Na(s) + Cl2(g) → NaCl(s)

The balanced equation is as follows:

2Na(s) + Cl2(g) → 2NaCl(s)

1 mole(71 g) of chlorine produces 2 moles(117  g) of sodium chloride

6 mole of chlorine gas will produce ? mole of sodium chloride

cross multiply

number of moles of NaCl produce = 6 × 2

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number of moles of NaCl produce = 12 mol

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3 years ago
A white rooster mates with a black hen. The offspring is gray in color. What is this phenomenon called?
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A. co dominace

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Explanation:

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3 years ago
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Answer:

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Addition of water to an alkyne gives a keto‑enol tautomer product. Draw an enol that is in equilibrium with the given ketone
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Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.

<h3>What is the keto-enol means in tautomer?</h3>

They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.

  1. The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
  2. If the ketone have been handled with bromine, little response might be visible because the enol content material might be too low.
  3. If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
  4. This might finally provide a bromoform product. Under acidic conditions, the enol might desire formation of the greater substituted enol constant with alkene stability.

7 0
2 years ago
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