A friend borrowed 5 different movies from the lib. in how many different orders can they watch the movies
2 answers:
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Answer:
1) solve x+1/x = 5
2) solve x³+1/x³
substitute x = 1/4 into the expression
You are being asked to compare various expressions to the given one, and to determine which are equivalent and which are not. You are asked to simplify the given expression—collect terms.
The given expression ...
... 4y -8x² -5 +14x² +y -1
can be simplified by identifying like terms and adding their coefficients.
... y(4 +1) +x²(-8 +14) +(-5 -1)
... = 5y +6x² -6 . . . . . simplified form
Any expression that has a different y-term, a different x² term, or a different constant term is <em>not equivalent</em>.
Once you have found this simplified expression, you can drag it to the appropriate box. Looking at the top three expressions on the left, you see immediately that they have different y-terms, so all those go to the "not equivalent" box. The expression on the bottom row has a different x² term, so it, too, is "not equivalent". (The sign is negative instead of positive. Details matter.)
The remaining expression, the one on the far right, has the appropriate y-term and constant term. The x² terms have not been combined, so it is equivalent, but not fully simplified.
Answer:
Option 3: (5, 1)
Step-by-step explanation:
There are several ways of solving for systems of linear equations, either through graphing, substitution, or elimination.
The graphing method is the easiest, as you only need to plot points on the graph using the y-intercepts and the slopes.
I will be demonstrating the <u>graphing method</u>.
Given the systems of linear equations:
Equation 1: y = x - 4
where the <u>slope</u>, <em>m</em> = 1, and <u>y-intercept </u>(0, -4).
Equation2: y = -x + 6
where the <u>slope</u>, <em>m </em>= -1, and <u>y-intercept</u> (0, 6).
The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b).
<h3>Graphing Instructions:</h3>For Equation 1, plot the y-intercept, (0, -4) on the graph. Then use the <u>slope</u>, m = 1 (rise 1 unit, run 1 unit) to plot other points on the graph. Repeat this process until you have enough points to connect a line with.
Repeat these same procedures for graphing Equation 2, start by plotting its y-intercept at (0, 6), and its slope, m = -1 (down 1 unit, run 1 unit).
<h3>Solution: </h3>
The intersection of both lines occurs at point, (5, 1), which is solution to the given systems of linear equations. Therefore, the correct answer is the third option, (5, 1).
Attached is the screenshot of the graphed systems of linear equations, where it shows the point of intersection at (5, 1).
