A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.
A cylindrical weight with a mass (m) of 3 kg is dropped, that is, its initial velocity (u) is 0 m/s and travels 10 m (s). Assuming the acceleration (a) is that of gravity (9.8 m/s²). We can calculate the velocity (v) of the weight in the instant prior to the collision with the piston using the following kinematic equation.
![v^{2} = u^{2} + 2as = 2 (9.8 m/s^{2} ) (10m) \\\\v = 14 m/s](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20u%5E%7B2%7D%20%2B%202as%20%3D%202%20%289.8%20m%2Fs%5E%7B2%7D%20%29%20%2810m%29%20%5C%5C%5C%5Cv%20%3D%2014%20m%2Fs)
The object with a mass of 3 kg collides with the piston at 14 m/s, The kinetic energy (K) of the object at that moment is:
![K = \frac{1}{2} m v^{2} = \frac{1}{2} (3kg) (14m/s)^{2} = 294 J](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20m%20v%5E%7B2%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%283kg%29%20%2814m%2Fs%29%5E%7B2%7D%20%3D%20294%20J)
The kinetic energy of the weight is completely converted into heat transferred into the gas cylinder. Thus, Q = 294 J.
Given all the process is at 250 K (T), we can calculate the change of entropy of the gas using the following expression.
![\Delta S_{gas} = \frac{Q}{T} = \frac{294 J}{250K} = 1.18 J/K](https://tex.z-dn.net/?f=%5CDelta%20S_%7Bgas%7D%20%3D%20%5Cfrac%7BQ%7D%7BT%7D%20%3D%20%5Cfrac%7B294%20J%7D%7B250K%7D%20%3D%201.18%20J%2FK)
The change in the entropy of the environment, has the same value but opposite sign than the change in the entropy of the gas. Thus, ![\Delta S_{env} = -1.18 J/K](https://tex.z-dn.net/?f=%5CDelta%20S_%7Benv%7D%20%3D%20-1.18%20J%2FK)
A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.
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Answer:
La constante de equilibrio (K) se expresa como la relación entre las concentraciones molares (mol/l) de reactivos y productos. Su valor en una reacción química depende de la temperatura, por lo que ésta siempre debe especificarse.
Explanation:
Explanation: Walking for 30 minutes covers a distance of 2.0 to 2.5 km and burns about 125 calories
Answer:
D
Explanation:
Question: Scientists can use many strategies during investigations, including heldwork, surveys,
models, and experiments. Which of these phrases best describes an experiment?
A mathematical analysis of data
B. observation of animals in their natural world
Ci collection of data from an uncontrolled environment for comparative purposes
D. procedure with controlled conditions and test and outcome variables
Answer:
True
Explanation:
The physical and chemical properties of a substance depend on the nature of intermolecular forces between its molecules. For instance, water has a high boiling point because of hydrogen bonding between water molecules. Liquid water is denser than ice because of the difference in the nature of hydrogen bonding in liquid water and ice.