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larisa86 [58]
2 years ago
14

Medical implants and high-quality jewelry items for body piercing are frequently known by a trade name, G23Ti, which means "surg

ical-grade" titanium. It is made up of 64.3% titanium, 24.19% aluminum and 11.42% vanadium.
What is the empirical formula that represents this material?
Chemistry
1 answer:
mrs_skeptik [129]2 years ago
7 0

Answer:

Ti6Al4V1 or Ti6Al4V

Explanation:

So, from the question above we are given the following Important data or parameters or information which is going to help us in solving this question and they are;

The "surgical-grade" titanium is made up of 64.3% titanium, 24.19% aluminum and 11.42% vanadium.

This is a stoichiometry Question so in order to be able to solve this question one must have the basic knowledge of stoichiometry, it is advisable that one revise it.

So, let us delve right into the solution of this question. Recall that, the formula for Calculating the number of moles = mass/molar mass.

Hence, the number of moles of titanium,Ti = 64.3/47.87 = 3 moles.

Also, the number of moles of aluminum = 24.19/26.98 = 0.8966

For vanadium; 11.42/51 = 0.22

The next step is to divide each number of moles component by the lowest number of mole, that is;

Ti = 1.34/ 0.22 = 6; Al = 0.8966/0.22= 4 and V = 0.22/0.22 = 1.

Thus, the emperical formula is = Ti6Al4V.

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A 1.87 L aqueous solution of KOH contains 155 g of KOH . The solution has a density of 1.29 g/mL . Calculate the molarity ( M ),
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Answer:        

[KOH] : 1.47 M

[KOH] : 1.22 m

[KOH]: 6.42 % mass percent.      

Explanation:

First of all we must determine the volume of solution. We have to work with the density

Density = mass / volume

1.29 g/ml = mass / 1870 ml

1.29 g/ml . 1870 ml = 2412.3

Now we must convert the mass to moles

155g / 56.1 g/ mol = 2.76 moles

Now we can calculate molarity

2.76 mol / 1.87 L = 1.47 M

To calculate molality we have to find out the mass of solvent

mass solute + mass solvent = mass solution

155 g + mass solvent = 2412.3 g

2412.3g - 155g = 2257.3g

We have to convert the 2257.3 g to kg

2257.3 g = 2.25 kg

molality = 2.76 moles / 2.25 kg = 1.22 m

To find out the % mass percentation, we have to calculate the mass of solute in 100 g of solution.

In 2412.3 g of solution we have 155 g of KOH

In 100 g of solution, we would have (100 . 155) / 2412.3 = 6.42 %mass percent.

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