Answer:
Final volume of the gas is 4.837mL
Explanation:
Initial volume (V1) = 350mL = 0.35L
Initial temperature (T1) = 0°C = (0 + 273.15)k = 273.15k
Initial pressure (P1) = 1.0atm
Final volume (V2) = ?
Final temperature (T2) = 10°C = (10 + 273.15)k = 283.15K
Final pressure (P2) = 75atm
To solve this question, we'll have to use combined gas equation which is the combination of all gas law I.e Charle's laws, Boyle's law, Pressure law etc.
According to combined gas equation,
(P1 × V1) / T1 = (P2 × V2) / T2
Make V2 the subject of formula,
V2 = (P1 × V1 × T2) / (P2 × T1)
V2 = (1.0 × 0.35 × 283.15) / (75 × 273.15)
V2 = 99.1025 / 20,486.25
V2 = 0.004837L
V2 = 4.837mL
The final volume of the gas is 4.837mL
The specific heat of a material is 0.137 J/g°C.
<u>Explanation:</u>
The specific heat formula relates the heat energy required to perform a certain reaction with the mass of the reactants, specific heat and the change in temperature during the reaction.
Q = mcΔT
Here m is the mass, Q is the heat energy required, ΔT is the change in temperature and c is the specific heat.
So, if we have to determine the specific heat of the object, then we have to determine the ratio of heat required to mass of the object with change in time, as shown below.

As mass of the object m is given as 35 g and the energy is said to be absorbed so Q = 96 J.
The temperature values given should be changed from kelvin to celsius first. So, initial temperature 293 K will become 293-273.15 = 19.85°C.
Similarly, the final temperature will be 313 - 273.15 = 39.85°C.
Then, ΔT = 39.85-19.85 = 20 °C
Then,

So, the specific heat of a material is 0.137 J/g°C.
Answer:
there is a little something called poop.
Explanation:
about that rasputia.
Answer:
Particles are constatantly moving and diffusing
This is possible because of diffusion
Explanation:
Hope this helps