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elena55 [62]
3 years ago
8

A sealed vessel containing sulfur dioxide and nitrogen has a total pressure of 520 Torr and partial pressures of 266 Torr nitrog

en. What is the partial pressure of sulfur dioxide in Torr?
Chemistry
1 answer:
mixer [17]3 years ago
8 0
The total pressure is the sum of all the partial pressures of the different components in the system. In this case, if the total pressure is 520 torr, and the partial pressure of nitrogen is 266 torr, and the only components are nitrogen and sulfur dioxide, this means that the rest of the pressure is all due to sulfur dioxide.
So the partial pressure of sulfur dioxide = 520 - 266 = 254 torr SO2.
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An aluminum can holds 350 mL of gas at 0 C and 1.0 atm. what is the new volume if the can is heated to 10 C and the pressure ins
Mademuasel [1]

Answer:

Final volume of the gas is 4.837mL

Explanation:

Initial volume (V1) = 350mL = 0.35L

Initial temperature (T1) = 0°C = (0 + 273.15)k = 273.15k

Initial pressure (P1) = 1.0atm

Final volume (V2) = ?

Final temperature (T2) = 10°C = (10 + 273.15)k = 283.15K

Final pressure (P2) = 75atm

To solve this question, we'll have to use combined gas equation which is the combination of all gas law I.e Charle's laws, Boyle's law, Pressure law etc.

According to combined gas equation,

(P1 × V1) / T1 = (P2 × V2) / T2

Make V2 the subject of formula,

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (1.0 × 0.35 × 283.15) / (75 × 273.15)

V2 = 99.1025 / 20,486.25

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5 0
2 years ago
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Determine the specific heat of a material if a 35. Gram sample absorbed 96. Joules of energy as it was heated from 293 K to 313
podryga [215]

The specific heat of a material is 0.137 J/g°C.

<u>Explanation:</u>

The specific heat formula relates the heat energy required to perform a certain reaction with the mass of the reactants, specific heat and the change in temperature during the reaction.

Q = mcΔT

Here m is the mass, Q is the heat energy required, ΔT is the change in temperature and c is the specific heat.

So, if we have to determine the specific heat of the object, then we have to determine the ratio of heat required to mass of the object with change in time, as shown below.

c = \frac{Q}{m\ \times\ delta\ T}

As mass of the object m is given as 35 g and the energy is said to be absorbed so Q = 96 J.

The temperature values given should be changed from kelvin to celsius first. So, initial temperature 293 K will become 293-273.15 = 19.85°C.

Similarly, the final temperature will be 313 - 273.15 = 39.85°C.

Then, ΔT = 39.85-19.85 = 20 °C

Then,

c = \frac{96}{35 \times 20} =\frac{96}{700}  = 0.137 J/g^{o}C

So, the specific heat of a material is 0.137 J/g°C.

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