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lina2011 [118]
3 years ago
9

The zinc case in the dry cell battery serves as the

Chemistry
1 answer:
Bogdan [553]3 years ago
5 0
C anode, forgive me if I am wrong
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B) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
snow_tiger [21]

Answer:

Explanation:

You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.

This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.

3 0
2 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°C _____.
MatroZZZ [7]

Answer:

c

Explanation:

1 calorie = 4.184J/g×°C

This also happens to be the specific heat capacity of water, which is the amount of energy it takes to raise the temperature of 1mL of water by 1°C

6 0
3 years ago
Dilute 0.407M & 2.56L solution to 7.005L. CF?
Alenkinab [10]

Answer:

C₂ = 0.149 M

Explanation:

Given data:

Initial concentration = 0.407 M

Initial volume = 2.56 L

Final volume = 7.005 L

Final concentration = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Initial concentration

V₁ = Initial volume

C₂ = Final concentration

V₂ =Final volume

Now we will put the values.

0.407 M × 2.56 L =  C₂ × 7.005 L

1.042 =  C₂ × 7.005 L

C₂ = 1.042 M.L / 7.005 L

C₂ = 0.149 M

5 0
2 years ago
The ai for sodium for adults is ______ milligrams per day.
andreev551 [17]

Answer:

1500 milligrams

6 0
2 years ago
8. Given the balanced chemical equation Br2 + 2 NaI -> 2 NaBr + I2 How many moles of sodium bromide (NaBr) could be produced
bezimeni [28]

Since we are already given the balanced equation:


Br_{2}+2NaI → NaBr+I_{2}


We can derive the molar ratios as: 1:2:1:1


That being said, we are given 0.172 moles of bromine (Br_{2}), so it has a ratio of 1:1 with sodium bromide (NaBr).


So we can take from that ratio, that when 0.172 moles of bromine are used, we are, in turn, going to get 0.172 moles of sodium bromide produced.

4 0
3 years ago
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