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valina [46]
4 years ago
5

How many formula units in MgCl2

Chemistry
2 answers:
nata0808 [166]4 years ago
8 0
So number of formula units in the MgCl2 sample = 21.4 g MgCl2 * [1 mol / 95.21 g] x [6.022 x 10²³ ...
soldier1979 [14.2K]4 years ago
6 0
The answer is around these numbers: 3,4,5,6
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NEED ANSWER FAST
Anarel [89]

Answer: Option (c) is the correct answer.

Explanation:

When current passes through a wire then a magnetic field is formed. Therefore, when two wires carry current in the same direction then both the wires with have respective magnetic fields in the same direction and their total magnetic field will be large.

But when current between two wires flow in opposite direction then the magnetic field produced will also be in opposite direction. Therefore, both the magnetic fields cancel each other out. Thus, total magnetic field will be small.

As a result, wires which carry current in the opposite direction repel each other.


5 0
4 years ago
Read 2 more answers
|
lilavasa [31]

1.66 M is the concentration of the chemist's working solution.

<h3>What is molarity?</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

In this case, we have a solution of Zn(NO₃)₂.

The chemist wants to prepare a dilute solution of this reactant.

The stock solution of the nitrate has a concentration of 4.93 M, and he wants to prepare 620 mL of a more dilute concentration of the same solution. He adds 210 mL of the stock and completes it with water until it reaches 620 mL.

We want to know the concentration of this diluted solution.

As we are working with the same solution, we can assume that the moles of the stock solution will be conserved in the diluted solution so:

n_1= n_2  (1)

and we also know that:

n = M x V_2

If we replace this expression in (1) we have:

M_1 x V_1= M_2 x V_2

Where 1, would be the stock solution and 2, the solution we want to prepare.

So, we already know the concentration and volume used of the stock solution and the desired volume of the diluted one, therefore, all we have to do is replace the given data in (2) and solve for the concentration which is M_2:

4.93 x 210 =  620 xM_2

M_2 = 1.66 M

This is the concentration of the solution prepared.

Learn more about molarity here:

brainly.com/question/19517011

#SPJ1

6 0
2 years ago
21.041gMg - 21.00gMg/ 24.31 (gmg/ mol Mg)
LenKa [72]

Answer:

molMG

Explanation:

8 0
3 years ago
What best describes the goals of scientific investigation and technological development?
bekas [8.4K]
Hi! I think the answer is option B. I hope
this helps, Goodluck :)
5 0
3 years ago
Which of the following statements about chemical and physical properties is false?
Ber [7]

Answer:

The odor of a substance is a physical property. That would be your answer.

Explanation:

Physical Properties

Physical properties are properties that can be measured or observed without changing the chemical nature of the substance. Some examples of physical properties are:

color (intensive)

density (intensive)

volume (extensive)

mass (extensive)

boiling point (intensive): the temperature at which a substance boils

melting point (intensive): the temperature at which a substance melts

Chemical Properties

Remember, the definition of a chemical property is that measuring that property must lead to a change in the substance’s chemical structure. Here are several examples of chemical properties:

Heat of combustion is the energy released when a compound undergoes complete combustion (burning) with oxygen. The symbol for the heat of combustion is ΔHc.

Chemical stability refers to whether a compound will react with water or air (chemically stable substances will not react). Hydrolysis and oxidation are two such reactions and are both chemical changes.

Flammability refers to whether a compound will burn when exposed to flame. Again, burning is a chemical reaction—commonly a high-temperature reaction in the presence of oxygen.

The preferred oxidation state is the lowest-energy oxidation state that a metal will undergo reactions in order to achieve (if another element is present to accept or donate electrons).

4 0
3 years ago
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