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3 years ago

How many atoms of oxygen are represented in 3Fe(NO3)2?

Chemistry

2 answers:

Jet001 [13]3 years ago

6 0

Answer:

18 atoms of oxygen are present

Explanation:

Atomicity of an atom in a compound is the total number of that atom present in that compound. In the question, 3 molecules of Iron(II)nitrate [Fe(NO₃)₂] contains the following number of oxygen.

In one molecule of Fe(NO₃)₂, number of oxygen atoms present is 3 × 2 = 6

If 6 atoms of oxygen are present in one molecule of Fe(NO₃)₂, in three molecules, 6 × 3 = 18 atoms of oxygen will be present in three molecules of Fe(NO₃)₂.

nexus9112 [7]3 years ago

4 0

There are 18. In each molecule of Fe(NO3)2 there are 6 oxygen atoms because you have 2 nitrate (NO3) components which each contain 3 oxygen atoms. 2 x 3 = 6. Because you have 3 molecules of Fe(NO3)2, you need to multiply 6 by 3, which gives you 18 oxygen atoms.

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<h2>Hello!</h2>

The answer is:

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The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

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R is the ideal gas constant (to work with pressure in mmHg), which is equal to:

$R=62.363\frac{mmHg.L}{mol.K}$

We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.

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$n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}$

$n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}\\\\n=\frac{2242mmHg.L}{18615.355\frac{mmHg.L}{mol.}}\\\\n=0.120mole$

Hence, we have that there were produced 0.120 moles of $CO_{2}$

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