Answer:
Action - Pulling up the train.
Reaction - Friction on the locomotive
Explanation:
Locomotive is pulling the train upwards ,
Which is the action force applied by the locomotive,
As a reaction locomotive will be pulled by the train which is the reaction of pulling
Now, considering it as a action on locomotive , friction force will act on it as a reaction upwards which will result to move it upwards.
For train action is pulling up by locomotive and reaction will be friction acting on it downwards.
Answer:
Hello todays answer should be False i am sorry if i am incorrect-Lucy
Explanation:
The interaction of electric currents or fields and magnetic fields.
Atoms is basic particles ,electrons,neutrons and the Regions of the atom are called electron shells and contain the electrons. So “a neutral core surrounded by mostly empty space”sounds pretty sure to me :)
The amount of energy lost to air friction, given the data is 37.71 J
<h3>How to obtain the initial energy</h3>
- Initial velocity (u) = 15.1 m/s
- Mass (m) = 450 g = 450 / 1000 = 0.45 Kg
- Initial Energy (E₁) = ?
E₁ = ½mu²
E₁ = ½ × 0.45 × 15.1²
E₁ = 51.3 J
<h3>How to obtain the final energy</h3>
- Final velocity (u) = 19.89 m/s
- Mass (m) = 450 g = 450 / 1000 = 0.45 Kg
- Final Energy (E₂) = ?
E₂ = ½mv²
E₂ = ½ × 0.45 × 19.89²
E₂ = 89.01 J
<h3>How to determine the energy lost</h3>
- Initial Energy (E₁) = 51.3 J
- Final Energy (E₂) = 89.01 J
- Energy lost =?
Energy lost = E₂ - E₁
Energy lost = 89.01 - 51.3
Energy lost = 37.71 J
Learn more about energy:
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